Question

我正在尝试从文本文件中删除“已删除的变量”。要删除以“＃Begin Removed Variable”开始并以“＃End Removed Variable”结束的数据。

模式如下：

# Begin Test Case

  File = ..\SVN\XXX.CPP
  Procedure = XX
  Procedure Number = 1
  Member Of = 1
  Creation Date = Jun XX 2019 14:36:44
  Description = This test is to verify 

    # Begin Variable

      Name = YY
      Decl_type = uchar*
      Usage = N
      TBrun Analysis = Compare
      Value = YY

    # End Variable

    # Begin Removed Variable

      Name = b_side_fired
      Decl_type = gun_class
      Usage = M

    # End Removed Variable

# End Test Case

我是新手，所以我无法判断和继续。

输出如下所示。删除所有“＃Begin Removed variables ....”的内容，并结束于“ End Removed variables”及其在文件中的所有出现。例如：如下所示，所有已删除的变量都将被删除。

# Begin Test Case

  File = ..\SVN\XXX.CPP
  Procedure = XX
  Procedure Number = 1
  Member Of = 1
  Creation Date = Jun XX 2019 14:36:44
  Description = This test is to verify 

    # Begin Variable

      Name = YY
      Decl_type = uchar*
      Usage = N
      TBrun Analysis = Compare
      Value = YY

    # End Variable
# End Test Case

Answer 1

单线可就地编辑文件：

 perl -ni -e 'print unless /# Begin Removed Variable/ .. /# End Removed Variable/' yourfile.txt

基本上，它仅打印行，除非它们位于那些已删除的块之一中。 More information关于标量..的使用。

用于比较的非原位awk版本（{,就像perl中的..）：

 awk '/# Begin Removed Variable/, /# End Removed Variable/ { next } 1' yourfile.txt

并完成：

sed '/# Begin Removed Variable/, /# End Removed Variable/ d' yourfile.txt

某些版本的sed支持-i进行Perl等就地编辑。

Answer 2

以下是如何完成此操作的示例：

    SELECT DISTINCT G.CITY FROM TBLGEOMARKET G,TBLGEOMARKET GM
    WHERE GM.ID = G.PARENTID AND GM.PARENTID = 15;

从.txt文件中删除多个已删除的变量

2 个答案: