Question

我正在使用带有CKKS方案的SEAL库，并且正在对双精度值进行批处理编码和加密，因此我想对它们进行求和。目前，我有这样的事情：

#include <iostream>
#include <vector>
#include <sstream>
#include "seal/seal.h"

int main()
{
    const vector<double> x_coordinates = { -3, -3, 3, 3 };
    const vector<double> y_coordinates = { -1, 0.5, 0.7, 1.7 };
    const vector<double> x_centers = { 0., 6 };
    const vector<double> y_centers = { 0., 6 };

    // Create encryption parameters
    EncryptionParameters params(scheme_type::CKKS);

    size_t poly_modulus_degree = 16384;
    params.set_poly_modulus_degree(poly_modulus_degree);
    params.set_coeff_modulus(CoeffModulus::Create(poly_modulus_degree, { 60, 40, 40, 60 }));

    cout << "Generating keys... ";
    auto context = SEALContext::Create(params);
    KeyGenerator keygen(context);
    auto public_key = keygen.public_key();
    auto secret_key = keygen.secret_key();
    auto relin_keys = keygen.relin_keys();
    Encryptor encryptor(context, public_key);
    Evaluator evaluator(context);
    Decryptor decryptor(context, secret_key);
    cout << "Done!" << endl;

    CKKSEncoder encoder(context);
    size_t slot_count = encoder.slot_count();
    double scale = pow(2.0, 40);

    cout << "\nSlots: " << slot_count << endl;
    cout << "Scale: " << scale << endl;

    double norm = 1. / x_coordinates.size();

    cout << "\nEcrypting coordinates... ";
    // Encode the input coordinates and centers.
    Plaintext plain_x, plain_y;
    Plaintext plain_x_center, plain_y_center;

    encoder.encode(x_coordinates, scale, plain_x);
    encoder.encode(y_coordinates, scale, plain_y);
    encoder.encode(x_centers, scale, plain_x_center);
    encoder.encode(y_centers, scale, plain_y_center);

    // Encrypt the encoded input coordinates and centers.
    Ciphertext encrypted_x, encrypted_y;
    Ciphertext encrypted_x_center, encrypted_y_center;

    encryptor.encrypt(plain_x, encrypted_x);
    encryptor.encrypt(plain_y, encrypted_y);
    encryptor.encrypt(plain_x_center, encrypted_x_center);
    encryptor.encrypt(plain_y_center, encrypted_y_center);

    // NOTE: Now I want to sum the values inside encrypted_x.
    Ciphertext result;
    evaluator.add_many(encrypted_x, result); // This won't work as we have single ciphertext.

    return 0;
}

因此，有没有一种方法可以对批加密值进行求和，而不是手动创建一个vector<Ciphertext>然后一个一个地加密每个输入值，最后像上面那样做add_many？ / p>

如何对SEAL同态加密的批加密输入求和？

0 个答案: