Question

我必须找到一个列表与另一个列表之间的区别。

但是这种寻找差异的过程使我每次跑步时的输出完全随机化。

下面是我的脚本

getALL = ["apple","ball","cat","dog","eagle"]  // initial list


Sourcee = ["eagle", "ball"]
diff = list(set(getALL) - set(Sourcee))
for items in diff:
    print(items)

有什么方法可以使diff列表的顺序与getALL相同？

我想要这样的输出：

apple
cat
dog

Answer 1

只需列表理解即可。（可选）将Sourcee转换为set会使其更快

>>> source_set = set(Sourcee)
>>> [e for e in getALL if e not in source_set]
['apple', 'cat', 'dog']

Answer 2

设置操作不保留顺序。但是，您可以通过检查原始列表中的顺序来重建差异列表。这适用于任何任意顺序。如果原始列表包含重复项，则会使事情复杂化。

getALL = ["apple","ball","cat","dog","eagle"]  # initial list


Sourcee = ["eagle", "ball"]
diff = list(set(getALL) - set(Sourcee))

original_order_diff = [x for x in getALL if x in diff]

print(original_order_diff)

Answer 3

使用sorted：

diff = list(set(getALL) - set(Source))
for items in sorted(diff, key=getALL.index):
    print(items)

甚至：

print('\n'.join([i for i in getALL if i not in Source]))

并且：

print(*[i for i in getALL if i not in Source], sep='\n')

将是最短的解决方案。

它们全部输出：

apple
cat
dog

找到两个列表的差异时如何维护输出列表的顺序

3 个答案: