Question

我正在尝试使用Python和tkinter编写此简单代码。每次我启动程序时，tkinter窗口都会正确弹出，如果我按“播放”，则循环开始。但是在那之后，如果我想使用“停止”按钮停止该过程，则程序没有响应。我认为我应该使用多进程或多线程，因为当周期开始时，接口无法正常工作。

我是Python的开始，所以请对我理解：D

我在Google上进行了搜索，但是发现的所有内容太复杂了，有人可以通过简单的方式解释该怎么做吗？

from pynput.keyboard import  Key, Controller as KeyboardController
from pynput.mouse import Button, Controller as MouseController
import time
import random
import string
import tkinter as tk

window = tk.Tk()
window.geometry("600x600")
window.title("Test")
window.resizable(False,False)

def arresta_programma():
    avvia_programma.destroy()

def avvia_programma():
    r = 0 
    n = 0
    l = 0
    d = 0  
    while n < 1000 : 
        keyboard= KeyboardController()
        keyboard.press('1')
        keyboard.release('1')
        time.sleep(random.randint(1,2))
        keyboard.press('1')
        keyboard.release('1')

        r = random.randint(1,4)

        if r == 1 and l <= 2:
            keyboard= KeyboardController()
            time.sleep(random.randint(1,2))
            keyboard.press(Key.left)
            time.sleep(random.randint(0,1))
            keyboard.release(Key.left)
            n = n + 1
            l = l + 1
            d = d - 1

first_button = tk.Button(text = "Play" , command = avvia_programma)
first_button.grid(row = 5, column = 5)

first_button = tk.Button(text = "Stop" , command = arresta_programma)
first_button.grid(row = 6, column = 6)

if __name__ == "__main__":
    window.mainloop()

即使用户按下“播放”按钮，我也希望程序做出响应。我还希望通过“停止”按钮打开界面，并准备再次按下“播放”。

Answer 1

正如您所说，至少应使用线程。您不能在您的代码（在本例中为tkinter处理）的mainLoop中使用time.sleep。大量的睡眠和循环会阻塞您的循环，并使其崩溃。

我建议创建一个从threading.Thread继承的类。下面的“播放”示例。

from threading import Thread
def execute_avvia():
    job = AvviaProgramma()
    job.setDaemon(True)
    job.start()

class AvviaProgramma(Thread):
    def __init__(self, *args, **kwargs):
        super(AvviaProgramma, self).__init__(*args, **kwargs)
        self.n = 0
        self.r = 0
        self.l = 0
        self.d = 0

    def run(self):
        while self.n < 1000:
            print(self.n)
            keyboard = KeyboardController()
            keyboard.press('1')
            keyboard.release('1')
            time.sleep(random.randint(1,2))
            keyboard.press('1')
            keyboard.release('1')

            r = random.randint(1, 4)

            if r == 1 and self.l <= 2:
                keyboard = KeyboardController()
                time.sleep(random.randint(1, 2))
                keyboard.press(Key.left)
                time.sleep(random.randint(0, 1))
                keyboard.release(Key.left)
                self.n = self.n + 1
                self.l = self.l + 1
                self.d = self.d - 1


first_button = tk.Button(text = "Play", command=execute_avvia)
first_button.grid(row = 5, column = 5)

如您所见，我在类方法的run（）中关闭了while循环，该循环取自Thread。这个解决方案并不完美，但是我希望对于初学者来说足够清楚。

祝你好运！

我在使用tkinter的python中的一个非常简单的程序时遇到问题

1 个答案: