我使用的是graphene-django
而不是rest api
(其余框架)。我正在进行用户注册。在其余框架中,验证是在序列化器部分完成的,但是当使用graphene
时,如何验证和处理将有意义的状态传递给客户端的错误?
这是注册码
class Register(graphene.Mutation):
class Arguments:
email = graphene.String(required=True)
password = graphene.String(required=True)
password_repeat = graphene.String(required=True)
user = graphene.Field(UserQuery)
success = graphene.Boolean()
errors = graphene.List(graphene.String)
@staticmethod
def mutate(self, info, email, password, password_repeat):
if password == password_repeat:
try:
user = User.objects.create(email=email)
user.set_password(password)
user.is_active = False
user.full_clean()
user.save()
return Register(success=True, user=user)
except ValidationError as e:
import pdb
pdb.set_trace()
return Register(success=False, errors=[e])
return Register(success=False, errors=['password', 'password is not matching'])
一个示例可以验证是否存在使用电子邮件的用户
答案 0 :(得分:1)
最简单的方法如下:
@staticmethod
def mutate(root, info, email, password, password_repeat):
errors = []
if password == password_repeat:
errors.append('password_is_not_matching')
if User.objects.filter(email=email).exists():
errors.append('email_is_already_registred')
if len(errors) == 0:
try:
user = User.objects.create(email=email)
user.set_password(password)
user.is_active = False
user.full_clean()
user.save()
return Register(success=True, user=user)
except ValidationError as e:
import pdb
pdb.set_trace()
return Register(success=False, errors=[e])
return Register(success=False, errors=errors)
但是,如果您进行大量此类检查,则可能会出现问题-代码变得更加复杂,并且更难弄清实际突变的作用。
有关更多信息,请阅读this article。