Question

我在Python中遇到字典问题。我是一个新学习者。我有一个正在处理的作业问题，正在努力解决作业问题。有人可以给我一些有关编码此问题的方法的想法吗？

＃我想知道一些有关如何开始这个家庭作业问题的想法。我已经尝试了很多东西，但仍然遇到麻烦。

trans = {'0':'ling', '1':'yi', '2':'er','3':'san', '4':'si','5':'wu', '6':'liu' ,'7':'qi', '8':'ba', '9':'jiu', '10':'shi'}

def convert_to_mandarin(us_num):
    ## us_num , a string representing a US number 0 to 99

convert_to_mandarin('26')将返回er shi liu； '30'，san shi。

有人可以帮我解决这个问题吗？

我在将数字打印到10以上时遇到麻烦。我应该编写一段代码，该代码将返回英文数字的中文“数字”（例如，应返回“ 36”的“ san shi liu” “。）如果是14，则应返回” shi si“。

trans = { '0':'ling', '1':'yi', '2':'er', '3':'san', '4':'si', '5':'wu', '6':'liu', '7':'qi', '8':'ba', '9':'jiu', '10':'shi'}

def convert_to_mandarian(us_num):
    ten = 'shi'
    chinese_trans = ''
    for n in str(us_num):
        if n in trans.keys():
            chinese_trans += trans[n]
        else:
            if n > 10:
                chinese_trans +=str(ten) + trans[str(us_num[-1:])]
            chinese_trans += trans[str(us_num[:1])] + str(ten) + trans[str(us_num[-1:])]

        if n == 10 or n == 20 or n == 30 or n == 40...........90:
            chinese_trans += trans[str(us_num[:1])] + str(ten)

    return chinese_trans


print(convert_to_mandarian('14'))will return shi si
--------------------------('36')will return san shi liu
--------------------------('20')will return er shi```


When I run my code, I only get less than 10. So, for example, for 36 I get "san-liu" instead of "san shi liu". What am I doing wrong? I'm a new learner of Python, so I'm sorry if this question isn't very specific.

Answer 1

尝试一下

trans = { '0':'ling', '1':'yi', '2':'er', '3':'san', '4':'si', '5':'wu', '6':'liu', '7':'qi', '8':'ba', '9':'jiu'}
def conv(number): #function which should accepts numbers
    try:
        num_str = str(number) #Converts to string
        if len(num_str) == 1:
            num_str = '0' + num_str #Adds e10 numeral position
        else:
            num_str = num_str[-2:] #Keeps last two digits
        if num_str[0] == '0':
            e10 = ''
            e01 = trans[num_str[1]] # Grabs the corresponding dictionary element for e01 position                   
        elif num_str[1] == '0':
            e10 = trans[num_str[0]] + '-shi' # Grabs the corresponding dictionary element for e10 position
            e01 = ''
        else:
            e10 = trans[num_str[0]] + '-shi' 
            e01 = ' ' + trans[num_str[1]] 
        return e10 + e01
    except Exception as e:
        print('Invalid input')

编辑：添加了一些例外情况

我对python字典有疑问

1 个答案: