Question

好的。所以。我试图用暴力破解不和谐链接的最后3个字母（这是难题的一部分，请不要判断我）。第一部分是众所周知的，因为如果有的话，由于多种明显的原因，整个事情就没有意义。我做了一个剧本。我使用了硒框架来访问邀请页面并搜索“邀请无效”消息。页面会一点一点地加载，因此我的脚本将等待标题栏完全加载，然后检查页面源是否包含：'Invite Invalid'（或'Einladungungültig'，因为discord检测到im的来源）。非常简单。但是：几个小时后，整个过程崩溃了。不仅如此，我的整个PC都无法再访问Internet（直到一切重启后，我重新启动它为止）。尽管并非总是在同一时间发生，但该错误是可重现的。知道为什么会这样吗？提前谢谢。

class title_bar_loaded(object):
    #callable, checks if title bar is loaded


import time
from _thread import start_new_thread
from selenium.webdriver.support.ui import WebDriverWait
from selenium import webdriver


# some stuff


threads_done = 0
thread_number = 4
timeout = 60
invites = []
starting_bit = 'http://discord.gg/akfs'
missing_letters = 3


def check_invite(b, driver):
    driver.get(b)
    try:  
        WebDriverWait(driver,timeout).until(title_bar_loaded())
    except:
        driver.refresh()
        return check_invite(b,driver)
    page = driver.page_source 
    return not 'Einladung ungültig' in str(page) # german because ip

def try_loop(num):
    global threads_done


    start = int(52**3 / thread_number * num)
    end = int(52**3 / thread_number * (num+1))

    driver= webdriver.Chrome('Z:/Downloads/chromedriver/chromedriver.exe')
    driver.implicitly_wait(timeout)

    driver.minimize_window()
    for i in range(start, end): # this loop goes through all possibilities
        invite = create(i)
        ok = check_invite(invite,driver)

        if ok:
            print(invite)
            invites.append(invite)

    threads_done += 1




def create(pos):


    #creates an invite link based on the number pos and the given part
    # 'akfs' so pos = 0 would be akfsaaa and pos = 1 would be akfsAaa
    # because for some reason caps matters in discord links


def main():


    # creates the threads, calls try_loop for each, but puts a different
    # number into every single one

    # keep script active after all threads have been started and print all 
    # invites after being done



if __name__ == '__main__':
    main()

重新启动之前没有互联网

0 个答案: