当元组中有多个没有成员的结构时,尝试在GCC上编译元组的比较会导致以下错误:
<source>: In function 'bool foo()':
<source>:120:16: error: request for member 'operator<' is ambiguous
120 | return a < b;
| ^
<source>:46:10: note: candidates are: 'bool N::operator<(const N&) const'
46 | bool operator<(const N &) const noexcept {
| ^~~~~~~~
<source>:46:10: note: 'bool N::operator<(const N&) const'
Compiler returned: 1
足够奇怪的是,当我绑定与元组中使用的相同类型时,它会按预期工作。一个空结构也可以,而两个不同类型的结构则不能。
使用clang或msvc进行编译会产生预期的结果。
这是正确的行为,还是GCC / libstdc ++错误?
({Try it,先取消注释所需的测试用例)
#include <tuple>
struct A {
int value;
A(int value) : value(value) {}
bool operator==(const A &other) const noexcept {
return value == other.value;
}
bool operator!=(const A &other) const noexcept {
return value != other.value;
}
bool operator<(const A &other) const noexcept {
return value < other.value;
}
};
struct N {
bool operator==(const N &) const noexcept {
return true;
}
bool operator!=(const N &) const noexcept {
return false;
}
bool operator<(const N &) const noexcept {
return false;
}
};
struct M {
bool operator==(const M &) const noexcept {
return true;
}
bool operator!=(const M &) const noexcept {
return false;
}
bool operator<(const M &) const noexcept {
return false;
}
};
using AAKey = std::tuple<A, A>;
using ANAKey = std::tuple<A, N, A>;
using ANANKey = std::tuple<A, N, A, N>;
using ANAMKey = std::tuple<A, N, A, M>;
using NKey = std::tuple<N>;
using NNKey = std::tuple<N, N>;
using NMKey = std::tuple<N, M>;
bool foo() {
/* Works
AAKey a{0, 1};
AAKey b{0, 0};
//*/
/* Works
ANAKey a{0, N{}, 1};
ANAKey b{0, N{}, 0};
//*/
/* Fails
ANANKey a{0, N{}, 0, N{}};
ANANKey b{0, N{}, 1, N{}};
//*/
/* Fails
ANAMKey a{0, N{}, 0, M{}};
ANAMKey b{0, N{}, 1, M{}};
//*/
/* Works
NKey a{N{}};
NKey b{N{}};
//*/
/* Fails
NNKey a{N{}, N{}};
NNKey b{N{}, N{}};
//*/
/* Fails
NMKey a{N{}, M{}};
NMKey b{N{}, M{}};
//*/
// Tying ANANKey into tuple:
/* Works
A ax1{0}, ay1{0}, ax2{0}, ay2{1};
N nx1, ny1, nx2, ny2;
auto a = std::tie(ax1, nx1, ax2, nx2);
auto b = std::tie(ay1, ny1, ay2, ny2);
//*/
return a < b;
}
外部运算符重载实际上可以工作(感谢@Turtlefight):
#include <tuple>
struct O {
friend bool operator==(const O &, const O &) noexcept {
return true;
}
friend bool operator!=(const O &, const O &) noexcept {
return false;
}
friend bool operator<(const O &, const O &) noexcept {
return false;
}
};
using OOKey = std::tuple<O, O>;
bool foo() {
OOKey a{O{}, O{}};
OOKey b{O{}, O{}};
return a < b;
}