为什么此Python pandas DataFrame代码不起作用？

Question

我的代码：

import pandas as pd
import matplotlib.pyplot as plt
%matplotlib inline
import seaborn as sns

income_vs_hardship = %sql SELECT per_capita_income_, hardship_index FROM chicago_socioeconomic_data;
plot = sns.jointplot(x='per_capita_income_',y='hardship_index', data=pd.DataFrame(income_vs_hardship))

正确答案：

import pandas as pd
import matplotlib.pyplot as plt
%matplotlib inline
import seaborn as sns

income_vs_hardship = %sql SELECT per_capita_income_, hardship_index FROM chicago_socioeconomic_data;
plot = sns.jointplot(x='per_capita_income_',y='hardship_index', data=income_vs_hardship.DataFrame())

唯一的区别：
data=pd.DataFrame(income_vs_hardship)与data=income_vs_hardship.DataFrame()

如果DataFrame是熊猫的一种方法，为什么我的代码不起作用。
错误显示“无法解释per_capita_income”。

Answer 1

DataFrame是pandas模块的类，而不是可应用于DataFrame实例的方法。

income_vs_hardship.DataFrame()无法用Python解释，因为income_vs_hardship没有DataFrame方法。相反，pd.DataFrame(income_vs_hardship)创建一个DtaFrame对象。