Question

我有一个表，每行包含一个日期和一些任意的数值。我需要将此值与特定但动态的日期间隔相加。

SELECT VERSION();
5.0.51a-24+lenny5

CREATE TABLE IF NOT EXISTS `work_entries` (
  `entry_id` int(10) unsigned NOT NULL auto_increment,
  `employee_id` tinyint(3) unsigned NOT NULL,
  `work_date` date NOT NULL,
  `hour_count` tinyint(3) unsigned NOT NULL,
  PRIMARY KEY  (`entry_id`)
);

INSERT INTO `work_entries` (`entry_id`, `employee_id`, `work_date`, `hour_count`) VALUES
(1, 1, '2011-04-25', 2),
(2, 1, '2011-04-26', 3),
(3, 1, '2011-04-27', 1),
(4, 2, '2011-04-25', 2),
(5, 2, '2011-04-27', 4),
(6, 1, '2011-05-08', 2),
(7, 2, '2011-05-06', 8),
(8, 2, '2011-05-08', 9),
(9, 2, '2011-05-09', 1),
(10, 1, '2011-05-29', 3),
(11, 1, '2011-05-30', 1),
(12, 2, '2011-05-30', 2),
(13, 1, '2011-06-02', 2),
(14, 1, '2011-06-04', 3),
(15, 1, '2011-06-14', 1),
(16, 2, '2011-06-14', 2),
(17, 2, '2011-06-17', 4),
(18, 1, '2011-06-18', 2),
(19, 2, '2011-06-19', 8),
(20, 2, '2011-06-26', 9),
(21, 2, '2011-07-01', 1),
(22, 1, '2011-07-03', 3),
(23, 1, '2011-07-03', 1),
(24, 2, '2011-07-16', 2);

以下查询返回上述数据集的正确输出，并应说明我要做的事情，但是，我需要根据work_date生成年和月值。日子（16,15）永远不会改变。具体来说，此查询将生成两行，一行用于指定的时间间隔，另一行用于其余时间，其中每个时段需要一行（N个月的第16个月为N + 15，所有月份的值为N + 1）。

SELECT
 SUM(hour_count) AS res
 FROM `work_entries`
 GROUP BY work_date
 BETWEEN '2011-04-16' AND '2011-05-15';

-- Outputs
res
----
44
32

-- Should give
res
----
32
14
28
 2

另一个正常工作但在错误的时间间隔（第01-31天）的示例：

SELECT
 SUM(hour_count) AS res
 FROM `work_entries`
 GROUP BY MONTH(work_date);

-- Outputs
res
---
12
26
31
 7

此外，如果有一种方法可以在同一时间输出起始日期和起始日期，我也会这样，但这不是很重要。

Answer 1

可爱：

SELECT
 SUM(hour_count)
 FROM `work_entries`
 GROUP BY
   YEAR(work_date - INTERVAL 15 DAY),
   MONTH(work_date - INTERVAL 15 DAY);

Answer 2

SELECT
  YEAR(grouping_date) AS year,
  MONTH(grouping_date) AS month,
  SUM(hour_count) AS hour_count_total
FROM (
  SELECT
    work_date,
    hour_count,
    work_date - INTERVAL 15 DAY AS grouping_date
  FROM work_entries
) x
GROUP BY
  YEAR(grouping_date),
  MONTH(grouping_date)

Answer 3

您可以使用另一个存储所有期间范围的表格。

create table `periods` (
  `id` int(11) not null auto_increment,
  `start` date default null,
  `end` date default null,
  primary key (`id`)
) engine=myisam auto_increment=4 default charset=latin1;


insert  into `periods`(`id`,`start`,`end`) values (1,'2011-04-16','2011-05-15');
insert  into `periods`(`id`,`start`,`end`) values (2,'2011-05-16','2011-06-15');
insert  into `periods`(`id`,`start`,`end`) values (3,'2011-06-16','2011-07-15');

并与之建立联接

select 
p.start,p.end,
sum(w.hour_count) as total
from periods as p
inner join work_entries as w
on w.work_date between p.start and p.end
group by p.start

+------------+------------+-------+
| start      | end        | total |
+------------+------------+-------+
| 2011-04-16 | 2011-05-15 |    32 |
| 2011-05-16 | 2011-06-15 |     6 |
+------------+------------+-------+
2 rows in set (0.00 sec)

然后，您可以在需要时添加where子句。

Answer 4

有点hackish，但

SELECT 
  SUM(hour_count),
  STR_TO_DATE(
    CONCAT(
      EXTRACT(YEAR_MONTH FROM work_date),
      '16'
    ),
    '%Y%m%d'
  ) AS startperiod,
  DATE_ADD(
    STR_TO_DATE(
      CONCAT(
        EXTRACT(YEAR_MONTH FROM work_date),
        '15'
      ),
      '%Y%m%d'
    ),
    INTERVAL 1 MONTH
  ) AS endperiod 
FROM
  work_entries 
GROUP BY work_date BETWEEN startperiod 
  AND endperiod;

考虑到这一点，上述内容根本不起作用。根据work_date字段是否落在生成的开始/结束时段内或外部，它只会返回两行。

基本上，您所需的查询需要的组间隔多于“会计月”而不是日历月。

Answer 5

SELECT
    YEAR(work_date) AS year,
    MONTH(work_date) AS month,
    case
        when right(work_date,2) between '01' and '15' then 1
        when right(work_date,2) between '16' and '31' then 2
    end 
    as partofmonth,
    SUM(hour_count) AS totalper15period
FROM work_entries
GROUP BY year, month, partofmonth

MySQL在日期范围内汇总值

5 个答案: