Question

如果我按如下所示插入新行：

$post = new Post();
$post->save();

是否可以直接调用上面创建的post_id并将其插入另一个表的新行中（而不是更改许多东西以从视图传递它）？

$post = new Post();
$post->save();
$talk = new Talk();
$talk->post_id = // I need to put here the post_id just created. Both inserts 
                //are in the same controller/method

Answer 1

您可以使用创建的帖子对象，因为保存后，帖子具有唯一的ID：

$post = new Post();
$post->save();
$talk = new Talk();
$talk->post_id = $post->id;

希望有帮助。

Answer 2

如果$post->id还不存在，您可以尝试一下

$post = new Post();
$post->save();
$post = $post->fresh();

$talk = new Talk();
$talk->post_id = $post->id;

Answer 3

您也可以执行此操作。使用Post::latest()->get()->take(1)->pluck('id');获取最新添加的内容。

例如以下示例：

$post = new Post();
$post->save();
$talk = new Talk();
$talk->post_id = Post::latest()->get()->take(1)->pluck('id');

->latest()

在控制器内传递新创建的行的ID

3 个答案: