Question

我正在使用CDK的Python包装器来创建Glue作业。 command属性需要类型为IResolvable | JobCommandProperty的对象。我试图在此处放置JobCommandProperty对象，但出现异常。

我创建了一个JobCommandProperty对象。我在某处寻找.builder()函数（类似于Java API），但找不到。

from aws_cdk import (
    aws_glue as glue,
    aws_iam as iam,
    core
)

class ScheduledGlueJob (core.Stack):

    def __init__(self, scope: core.Construct, id: str, **kwargs) -> None:
        super().__init__(scope, id, **kwargs)

        policy_statement = iam.PolicyStatement(
                actions=['logs:*','s3:*','ec2:*','iam:*','cloudwatch:*','dynamodb:*','glue:*']
            )

        policy_statement.add_all_resources()

        glue_job_role = iam.Role(
            self,
            'Glue-Job-Role',
            assumed_by=iam.ServicePrincipal('glue.amazonaws.com')
        ).add_to_policy(
            policy_statement
        )

        job = glue.CfnJob(
            self,
            'glue-test-job',
            role=glue_job_role,
            allocated_capacity=10,
            command=glue.CfnJob.JobCommandProperty(
                name='glueetl',
                script_location='s3://my-bucket/glue-scripts/job.scala'
            ))

错误消息是这样的：

$cdk synth
Traceback (most recent call last):
  File "app.py", line 30, in <module>
    glue_job = ScheduledGlueJob(app, 'Cronned-Glue-Job')
  File "/Users/d439087/IdeaProjects/ds/test_cdk/.env/lib/python3.7/site-packages/jsii/_runtime.py", line 66, in __call__
    inst = super().__call__(*args, **kwargs)
  File "/Users/d439087/IdeaProjects/ds/test_cdk/glue/scheduled_job.py", line 33, in __init__
    script_location='s3://my-bucket/glue-scripts/job.scala'
  File "/Users/d439087/IdeaProjects/ds/test_cdk/.env/lib/python3.7/site-packages/jsii/_runtime.py", line 66, in __call__
    inst = super().__call__(*args, **kwargs)
  File "/Users/d439087/IdeaProjects/ds/test_cdk/.env/lib/python3.7/site-packages/aws_cdk/aws_glue/__init__.py", line 2040, in __init__
    jsii.create(CfnJob, self, [scope, id, props])
  File "/Users/d439087/IdeaProjects/ds/test_cdk/.env/lib/python3.7/site-packages/jsii/_kernel/__init__.py", line 208, in create
    overrides=overrides,
  File "/Users/d439087/IdeaProjects/ds/test_cdk/.env/lib/python3.7/site-packages/jsii/_kernel/providers/process.py", line 331, in create
    return self._process.send(request, CreateResponse)
  File "/Users/d439087/IdeaProjects/ds/test_cdk/.env/lib/python3.7/site-packages/jsii/_kernel/providers/process.py", line 316, in send
    raise JSIIError(resp.error) from JavaScriptError(resp.stack)
jsii.errors.JSIIError: Expected 'string', got true (boolean)

也许有人有一个有效的CDK（python）示例来创建CfnJob对象？

Answer 1

没关系，role属性的类型必须为string，我对JSII错误消息感到困惑。

Answer 2

请注意，crawler与job不同，尽管如此，我认为权限是相似的。截至2020年8月16日，此功能已为爬虫工作（不幸的是，以前的答案都没有）

from aws_cdk import (
    aws_iam as iam,
    aws_glue as glue,
    core
)

class MyDataScienceStack(core.Stack):

    def __init__(self, scope: core.Construct, id: str, **kwargs) -> None:
        super().__init__(scope, id, **kwargs)

        statement = iam.PolicyStatement(actions=["s3:GetObject","s3:PutObject"],
                                        resources=["arn:aws:s3:::mybucketname",
                                                    "arn:aws:s3:::mybucketname/data_warehouse/units/*"])
        write_to_s3_policy = iam.PolicyDocument(statements=[statement])
        glue_role = iam.Role(
            self, 'GlueCrawlerFormyDataScienceRole',
            role_name = 'GlueCrawlerFormyDataScienceRole',
            inline_policies=[write_to_s3_policy],
            assumed_by=iam.ServicePrincipal('glue.amazonaws.com'),
            managed_policies=[iam.ManagedPolicy.from_aws_managed_policy_name('service-role/AWSGlueServiceRole')]
        )

        glue_crawler = glue.CfnCrawler(
            self, 'glue-crawler-id',
            description="Glue Crawler for my-data-science-s3",
            name='any name',
            database_name='units',
            schedule={"scheduleExpression": "cron(5 * * * ? *)"},
            role=glue_role.role_arn,
            targets={"s3Targets": [{"path": "s3://mybucketname/data_warehouse/units"}]}
        )

Answer 3

glue_job_role 变量的类型不再是“角色”，因为您已向其中添加了.add_to_policy。下面的代码应该可以工作。

glue_job_role = iam.Role(
            self,
            'Glue-Job-Role',
            assumed_by=iam.ServicePrincipal('glue.amazonaws.com')
        )
glue_job_role.add_to_policy(
            policy_statement
        )
job = glue.CfnJob(
            self,
            'glue-test-job',
            role=glue_job_role.arn,
            allocated_capacity=10,
            command=glue.CfnJob.JobCommandProperty(
                name='glueetl',
                script_location='s3://my-bucket/glue-scripts/job.scala'
            ))

使用AWS CDK（python）创建Glue作业失败

3 个答案: