Question

{
   "Flight1":{
      "3":{
         "id":"10",
         "name":"JumboJet1B",
         "level":"1",
         "category":"1",
         "energy":"10",
         "bonus":"10",
         "completed":0
      },
      "4":{
         "id":"10",
         "name":"JumboJet1B",
         "level":"1",
         "category":"1",
         "energy":"10",
         "bonus":"10",
         "completed":0
      }
   }
}

这是json输出

如何解析3和4中的项目，比如获取id，energy和name

谢谢！

Answer 1

如果Flight1中的订单无关紧要，则以下内容应该有效：

NSDictionary *flights = … // result from a JSON parser
NSDictionary *flight1 = [flights objectForKey:@"Flight1"];

for (NSString *key in [flight1 allKeys]) {
    NSDictionary *flight1Entry = [flight1 objectForKey:key];

    NSString *entryId = [flight1Entry objectForKey:@"id"];
    NSString *entryName = [flight1Entry objectForKey:@"name"];
    NSString *entryEnergy = [flight1Entry objectForKey:@"energy"];

    …
}

否则，如果您希望按照其数值排序键：

NSDictionary *flights = … // result from a JSON parser
NSDictionary *flight1 = [flights objectForKey:@"Flight1"];
NSArray *flight1Keys = [[flight1 allKeys] sortedArrayUsingComparator:^(id o1, id o2) {
    NSInteger i1 = [o1 integerValue];
    NSInteger i2 = [o2 integerValue];
    NSComparisonResult result;

    if (i1 > i2) result = NSOrderedDescending;
    else if (i1 < i2) result = NSOrderedAscending;
    else result = NSOrderedSame;

    return result;
}];

for (NSString *key in flight1Keys) {
    NSDictionary *flight1Entry = [flight1 objectForKey:key];

    NSString *entryId = [flight1Entry objectForKey:@"id"];
    NSString *entryName = [flight1Entry objectForKey:@"name"];
    NSString *entryEnergy = [flight1Entry objectForKey:@"energy"];

    …
}

Answer 2

假设您使用的是json framework，您可以像这样访问它：

NSDictionary *jsonDict = [jsonString JSONValue];

NSString *id = [[[jsonDict objectForKey:@"Flight1"] objectForKey:@"3"] objectForKey:@"id"];

这假定很多，所以使用try除了块或迭代不同的级别。

使用Objective-C进行复杂的JSON解析

2 个答案: