我可以使用以下方法在此page中传播和显示xml ..
private void loadTopMoversData() {
ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
try {
String xml = XMLfunctions.getXML(TOPMOVERS_XML);
Document doc = XMLfunctions.XMLfromString(xml);
NodeList nodes = doc.getElementsByTagName("scrip");
for (int i = 0; i < nodes.getLength(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element)nodes.item(i);
map.put("name", XMLfunctions.getValue(e, "name"));
map.put("currprice", XMLfunctions.getValue(e, "currprice"));
map.put("percentage", XMLfunctions.getValue(e, "percentage"));
map.put("code", XMLfunctions.getValue(e, "code"));
mylist.add(map);
Log.i("tag", XMLfunctions.getValue(e, "headline") + " " + XMLfunctions.getValue(e, "time") );
}
}
但我无法使用相同的方法解析此page中的xml,但使用适当的标记。我做错了什么?
private void loadNewsData() {
ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
try {
String xml = XMLfunctions.getXML(NEWS_XML);
Document doc = XMLfunctions.XMLfromString(xml);
NodeList nodes = doc.getElementsByTagName("data");
ArrayList<String> links = new ArrayList<String>();
for (int i = 0; i < nodes.getLength(); i++) {
Element e = (Element)nodes.item(i);
HashMap<String, String> map = new HashMap<String, String>();
map.put("headline", XMLfunctions.getValue(e, "headline"));
map.put("link", XMLfunctions.getValue(e, "link"));
map.put("time", XMLfunctions.getValue(e, "time"));
links.add(XMLfunctions.getValue(e, "link"));
mylist.add(map);
Log.i("tag", XMLfunctions.getValue(e, "headline") + " " + XMLfunctions.getValue(e, "time") );
}
} catch (Exception e) {
Log.e("tag", e.getMessage());
}
}`
这是我的XmlFunctions.java
public class XMLfunctions {
public final static Document XMLfromString(String xml){
Document doc = null;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
} catch (ParserConfigurationException e) {
System.out.println("XML parse error: " + e.getMessage());
return null;
} catch (SAXException e) {
System.out.println("Wrong XML file structure: " + e.getMessage());
return null;
} catch (IOException e) {
System.out.println("I/O exeption: " + e.getMessage());
return null;
}
return doc;
}
public final static String getElementValue( Node elem ) {
Node kid;
if( elem != null){
if (elem.hasChildNodes()){
for( kid = elem.getFirstChild(); kid != null; kid = kid.getNextSibling() ){
if( kid.getNodeType() == Node.TEXT_NODE ){
return kid.getNodeValue();
}
}
}
}
return "";
}
public static String getXML(String webURL){
String line = null;
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(webURL);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
line = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
} catch (MalformedURLException e) {
line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
} catch (IOException e) {
line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
}
return line;
}
public static int numResults(Document doc){
Node results = doc.getDocumentElement();
int res = -1;
try{
res = Integer.valueOf(results.getAttributes().getNamedItem("count").getNodeValue());
}catch(Exception e ){
res = -1;
}
return res;
}
public static String getValue(Element item, String str) {
NodeList n = item.getElementsByTagName(str);
return XMLfunctions.getElementValue(n.item(0));
}
}
是否与xml文件有关?请帮忙。感谢
修改 也有人可以告诉我如何使用'&amp;'来解析XML用这个解析器吗?
答案 0 :(得分:0)
您可能需要重新检查xml节点名称,区分大小写。另外检查链接数组是否正常?
答案 1 :(得分:0)
我弄明白了这个问题。在XMLfunctions.java中,它检查节点是否是TEXT_NODE,并且显然xml中的节点不是一个..
if( kid.getNodeType() == Node.TEXT_NODE ){
return kid.getNodeValue();
}
所以,我删除了条件,现在它正常工作。感谢
答案 2 :(得分:0)