我正在尝试使用createContext,useReducer和useContext在React Native中实现Redux概念。以下是我的代码文件:
Store.tsx
4
App.tsx
import React, { useReducer, createContext } from "react";
import { View, Text, StyleSheet, Button } from "react-native";
export const myContext = createContext();
export default function Store(props) {
const counter = 0;
const [state, dispatch] = useReducer((state, action) => {
return state + action;
}, counter);
return (
<myContext.Provider value={{ state, dispatch }}>
{props.children}
</myContext.Provider>
);
}
我不确定为什么我无法在useContex中访问“状态”。我收到错误消息“ 无法读取未定义的属性'状态'” 请帮忙。如果您也可以给出详细的解释,那将非常有帮助。
答案 0 :(得分:0)
您只能在上下文提供者的子组件中访问上下文的值。在这种情况下,您将在Store中调用呈现提供者的上方的useContext。在这些情况下,将提供传递给createContext的默认值。在这种情况下,createContext()
没有给出默认值,因此未定义。因此,尝试破坏未定义的const { state, dispatch } = useContext(myContext);
会导致您看到错误。
只需添加其他子组件即可使其工作。像这样:
import React, { useState, useContext, useEffect, createContext } from "react";
import { View, Text, StyleSheet, Button } from "react-native";
import Store, { myContext } from "./components/Store";
export default function AppWrapper(): JSX.Element {
// Store, renders the provider, so the context will be accessible from App.
return (
<Store>
<App />
</Store>
)
}
function App(): JSX.Element {
const { state, dispatch } = useContext(myContext);
return (
<View style={styles.wrapper}>
<Text>HEY</Text>
<Text>Counter: {state}</Text>
<Button title="Incr" onPress={() => dispatch(1)} />
<Button title="Decr" onPress={() => dispatch(-1)} />
</View>
);
}
const styles = StyleSheet.create({
wrapper: {
marginTop: 100
}
});