Question

我有一个递归异步函数getResponse(url,attempts = 0)，该函数轮询外部api的响应，并在达到X次重试次数或服务器错误后解析或退出。但是，它的内部“时钟”基于重试的次数（允许延迟以避免速率限制后），但是我还希望在设置基于时间的计时器方面具有灵活性，这将解决该功能并结束递归。理想情况下，我希望能够将基于时间的计时器包装在我的递归异步函数周围，例如timed(getResponse(url),3400)

通过将两个计时器打包到一个异步函数中，并将本地变量expired用作退出标志，并将Promise.race条件设置为on，我只能设法同时使用基于时间和基于“重试”的计时器这两个功能。

async function timedgetResponse (expiry = 3500,url) {
  let expired = false;
  async function timeout(expiry){
    await new Promise(_=> setTimeout(_,expiry));
    expired = true;
    return false;
  };

async function getResponse(url,attempts = 0){
  try {
    if(expired){ return false; };
    const limit = 10;
    if(attempts >= limit){ok: false, e:"MAX_ATTEMPTS"};
    const rawRes = await fetch(url,
      {
        method: 'GET',
        credentials: 'include', 
        headers: {
          'Accept': 'application/json'
        }
      });
    if (!rawRes.ok) {  throw (Error('SERVER_ERROR')); }; 
    const res = await rawRes.json(); 
    if(!res || res.status === 0){ throw (Error(res.request)); };
    return {ok: true, res: res.request};
  } catch(e){
  const err = e.message; 
  if(err === "RESPONSE_NOT_READY"){
    await new Promise(_ => setTimeout(_, 333));
    attempts +=1;   
    return getResponse(url,attempts);
  } else 
  if(err === "SERVER_ERROR_ON_RESOLVER"){
    await new Promise(_ => setTimeout(_, 10000));
    attempts +=1;       
    return getResponse(url,attempts);
  } else {
    return {ok: false, e:"MISC_ERROR"};
  };

};    
};

  const awaited = await Promise.race([
    getResponse(url),
    timeout(expiry)
  ]);

return awaited;
};

我认为这不是正确的方法，希望能为timed(getResponse(url),3400)解决方案提供帮助。

Answer 1

我有一个可能满足您需要的功能。我已经根据我对您的需求的理解对其进行了更新。想法是您将轮询直到某些事情成为事实，即解决或您超过最大尝试次数。它具有内置的可配置延迟。

这里的想法是您传递一个包装您的fetch调用的函数，该函数最终将解决/拒绝。

setPolling（pollFunc，freq = 1000，maxAttempts = 3）

pollFunc =不带参数的函数，并返回最终解决或拒绝的承诺。

freq =以毫秒为单位运行pollFunc的频率

maxAttempts =放弃前的最大尝试次数

const setPolling = async (pollFunc, freq = 1000, maxAttempts = 3, _attempts = 1) => {
  const wait = (delay) => new Promise(resolve=>setTimeout(resolve, delay))
  try {
    return await pollFunc()
  } catch (e) {
    if (_attempts < maxAttempts) {
      await wait(freq)
      return await setPolling(pollFunc, freq, maxAttempts, ++_attempts)
    }
    throw (e instanceof Error) ? e : new Error((typeof e !== 'undefined') ? e : 'setPolling maxAttempts exceeded!')
  }
}

async function alwaysFail() {
    throw new Error(`alwaysFail, failed because that's what it does!`)
}

function passAfter(x) {
  let i = 0
  return async ()=> {
    if (i > x) return `passAfter succeeded because i(${i}) > x(${x})`
    throw new Error(`i(${i++}) < x(${x})`)
  }
}

setPolling(alwaysFail)
  .catch((e)=>console.error(`alwaysFail, failed!\n${e.message}\n${e.stack}`))

setPolling(passAfter(5), 500, 10)
  .then((res)=>console.log(`passAfter, succeeded!\n${res}`))
  .catch((e)=>console.error(`passAfter, failed!\n${e.message}\n${e.stack}`))

Answer 2

根据您想在计时器到期时停止重试的情况，可以使用token将停止信号传递给递归过程。

应该执行以下操作：

const poll = async (work, options, token) => {
    const settings = Object.assign({ 'delay':0, 'attempts':1, 'maxAttempts':3 }, options);

    // Utility function which returns a Promise-wrapped setTimeout
    const delay = (ms) => new Promise(resolve => setTimeout(resolve, ms));

    // Two mechanisms for stopping the recursion.
    // Performing the tests here ensures they are applied before the first work() call.
    // 1. token-borne stop signal 
    if(token.stop) {
        throw new Error('poll(): stopped');
    }
    // 2. max attempts reached
    if (settings.attempts >= settings.maxAttempts) {
        throw new Error('poll(): max attempts reached');
    }

    // Do the work, and recurse on error
    try {
        return await work();
    }
    catch (e) {
        await delay(settings.delay);
        settings.attempts += 1; // Mutate/pass `settings`; the original `options` is not guaranteed to have an `attempts` property.
        return await poll(work, settings, token);
    }
}

致电如下：

// token
const token = {}; // or {'stop':false} if you like

// Time based timer:
setTimeout(() => {
    token.stop = true; // raise the 'stop' flag
}, 60000); // or whatever

let pollPromise = poll(doSomethingAsync, {'delay':1000, 'maxAttempts':100}, token)
.then((res) => console.log(res))
.catch((e) => console.error(e));

请注意，在设置停止信号时：

对飞行中工作的成功回应仍然会通过。
将阻止进一步递归，但不会尝试中止正在进行的工作。

再想一想，这些行为可能会根据所需的具体情况而改变。

计时器包装函数，用于递归异步/等待调用

2 个答案: