每当我尝试使用以下功能删除给定节点之后的节点时,都会出现分段错误
我一直在寻找类似的问题,解决方案说要在已经完成的标题中检查NULL
struct node *delete_aft(struct node *start)
{
struct node *ptr,*nextptr;
int x;
printf("\nEnter the previous element of the element to be deleted ");
scanf("%d",&x);
ptr=start;
ptr->next=nextptr;
while(ptr!=NULL&&ptr->next!=NULL)
{
if(ptr->data==x)
{
ptr->next=nextptr->next;
free(nextptr);
goto exit;
}
else
{
ptr=nextptr;
nextptr=nextptr->next;
}
}
if(ptr->next==NULL)
printf("\n Element not found");
exit:return start;
}
答案 0 :(得分:0)
我注释了我进行更改的代码。
struct node *delete_aft(struct node *start)
{
struct node *ptr,*nextptr;
int x;
printf("\nEnter the previous element of the element to be deleted ");
scanf("%d",&x);
ptr = start;
while (ptr != NULL && ptr->next != NULL)
{
if (ptr->data == x)
{
// Make temporary copy of ptr->next.
nextptr = ptr->next;
// Set ptr->next to the node after ptr->next, i.e. ptr->next->next.
ptr->next = nextptr->next;
free(nextptr);
goto exit;
}
else
{
// Search the next node.
ptr = ptr->next;
}
}
// If we reach this point, then x was not found, or x was the last node.
if(ptr->next == NULL)
printf("\n Element not found");
exit:return start;
}