如何仅在那些情况正确的情况下删除contenteditable属性

Question

我认为这对那些了解它的人来说很简单：-）

我想删除所有具有不属性contenteditable =“ false”的元素的“ conteneditable”属性。因此，仅删除那些具有“ contenteditable = true”的内容。

我该怎么做？ 这将删除所有元素上的

$('body *', iframe).removeAttr('contenteditable');

Answer 1

属性选择器：SessionToken

Answer 2

我相信您可以使用def DrawPointsOnTail(canvas): global tailSegments, centerPoint, endPoint, midPoint, tailLength currentBezierLength = BezierLength(centerPoint.position, midPoint.position, endPoint.position, 100) print (currentBezierLength) #if (currentBezierLength < tailLength): distanceBetweenPoints = currentBezierLength / tailSegments #else: #distanceBetweenPoints = tailLength / tailSegments for i in range(0, tailSegments): currentSegment = Point(BezierCurve(centerPoint.position, midPoint.position, endPoint.position, (i * distanceBetweenPoints) / currentBezierLength), 3, "Blue") currentSegment.draw(canvas) 函数。

请参见here