我想将图像发送到服务器并以json格式获取结果,但是应用程序返回网络请求失败错误
使用genymotion作为模拟器来反应本机0.6
我尝试了RNFetchblob,但结果需要很长时间才能获得响应(5分钟) 我也尝试过axios,但它以200 ok响应空数据
这是导入图像的功能
OnClick = () => {
ImagePicker.showImagePicker(options, response => {
console.log("Response = ", response);
if (response.didCancel) {
console.log("User cancelled image picker");
} else if (response.error) {
console.log("Image Picker Error: ", response.error);
} else {
let source = { uri: response.uri };
// You can also display the image using data:
//let source = { uri: 'data:image/jpeg;base64,' + response.data };
this.setState({
avatarSource: source,
data: response.data,
BtnDisabled: false
});
console.log();
}
});
};
以及这种发送图像的方法
Send = async () => {
let url = "http://web001.XXX.com:8000/api/prediction/check_prediction/";
let UplodedFile = new FormData();
UplodedFile.append('file',{ type:'image/jpeg', uri : this.state.avatarSource , name:'file.jpeg'});
fetch(url, {
method: 'POST',
body:UplodedFile
})
.then(response => response.json())
.then(response => {
console.log("success");
console.log(response);
})
.catch(error => {
console.error(error);
});
我希望json格式
答案 0 :(得分:0)
您可以这样更改代码吗?
OnClick = () => {
ImagePicker.showImagePicker(options, response => {
console.log("Response = ", response);
if (response.didCancel) {
console.log("User cancelled image picker");
} else if (response.error) {
console.log("Image Picker Error: ", response.error);
} else {
let source = { uri: response.uri };
// You can also display the image using data:
//let source = { uri: 'data:image/jpeg;base64,' + response.data };
this.setState({
pickerResponse: response,
data: response.data,
BtnDisabled: false
});
console.log();
}
});
};
Send = async () => {
let url = "http://web001.XXX.com:8000/api/prediction/check_prediction/";
let UplodedFile = new FormData();
UplodedFile.append('file',{ type:'image/jpeg', uri : this.state.pickerResponse.path , name:'file.jpeg'});
axios({
method: "post",
url: url,
data: UplodedFile
})
.then(response => {
console.log("success");
console.log(response);
})
.catch(error => {
console.error(error);
});