Question

运行查询时出错：

System.Data.SqlClient.SqlException（0x80131904）：子查询返回了多个值。当子查询遵循=，！=，<，<=，>，> =或将子查询用作表达式时，不允许这样做

这是我的代码：

UPDATE Trade
SET Reference = (SELECT DISTINCT temp.MainRecordNo
                 FROM temp
                 WHERE temp.SubRecordNo = Trade.TradeNo 
                   AND temp.LinkType = 'ATPD'
                   AND LinkStatus = 'A'
                   AND ISNULL(Trade.Reference, '') <> Temp.MainRecordNo)
WHERE EXISTS (SELECT DISTINCT Temp.MainRecordNo
              FROM Temp
              WHERE Temp.SubRecordNo = Trade.TradeNo
                AND Temp.LinkType = 'ATPD'
                AND LinkStatus = 'A'
                AND ISNULL(Trade.CstpReference, '') <> Temp.MainRecordNo)

如何解决？

Answer 1

首先，您应该使用JOIN重新命名：

UPDATE t
    set Reference = temp.MainRecordNo
FROM Trade t JOIN
     temp
     ON Temp.SubRecordNo = t.TradeNo
WHERE temp.LinkType = 'ATPD' AND
      temp.LinkStatus = 'A' AND  -- Guessing this comes from temp
      (t.CstpReference IS NULL OR t.CstpReference <> Temp.MainRecordNo);

这将解决您的直接问题。您还有另一个问题，就是temp中的多个记录与Trade中的单个记录匹配。目前还不清楚如何解决该问题。这将使用任意匹配行中的值进行更新。

Answer 2

为您自己尝试，请在不确定top 1返回的update的数量rows时在subquery查询中选择Update Trade set Reference = (Select top 1 distinct temp.MainRecordNo from temp where temp.SubRecordNo = Trade.TradeNo and temp.LinkType = 'ATPD' and LinkStatus = 'A' and isnull(Trade.Reference,'') <> Temp.MainRecordNo) WHERE EXISTS ( SELECT DISTINCT Temp.MainRecordNo FROM Temp where Temp.SubRecordNo = Trade.TradeNo and Temp.LinkType = 'ATPD' and LinkStatus = 'A' and isnull(Trade.CstpReference,'') <> Temp.MainRecordNo)：-

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收到错误：SqlException（0x80131904）：子查询返回了多个值-为什么？

2 个答案: