我有一棵树,我会撒谎为它添加更多的叶子。但是,如果一个叶子可以分配给多个节点,那么我希望它是一个单独的节点。
我尝试编写此函数:
输入1:data.frame
testDF <- data.frame(
Reads = c("Read1", "Read1", "Read1", "Read2", "Read3", "Read4", "Read5"),
Features = c(
"Feature1", "Feature2", "Feature3",
"Feature4", "Feature5", "Feature6",
"Feature7"
),
stringsAsFactors = F
)
testDF
Reads Features
1 Read1 Feature1
2 Read1 Feature2
3 Read1 Feature3
4 Read2 Feature4
5 Read3 Feature5
6 Read4 Feature6
7 Read5 Feature7
输入2:data.tree
testTree <- as.Node(
data.frame(
pathString = c("Root/Feature1/F1",
"Root/Feature1/F2",
"Root/Feature3/F3")
)
)
testTree
levelName
1 Root
2 ¦--Feature1
3 ¦ ¦--F1
4 ¦ °--F2
5 °--Feature3
6 °--F3
给出以下2个输入:
Root
¦--Read1
¦--Feature1
¦ ¦--F1
¦ °--F2
¦--Feature2
¦--Feature3
¦ °--F3
¦--Feature4
¦ °--Read2
¦--Feature5
¦ °--Read3
¦--Feature6
¦ °--Read4
°--Feature7
°--Read5
因此,由于Read1
可以分配给多个要素(要素1,要素1和要素3),因此我想将其分配给上层节点。