Question

我想在词典列表中选择条目，以便创建仅包含我所需的不同项目的新词典。

例如，从此列表开始：

List<Dictionary<string, string>> test = new List<Dictionary<string, string>>{            
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret B"}, {"idtGroupe", "idtLivretB"}, {"variables", "test2"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret B"}, {"idtGroupe", "idtLivretB"}, {"variables", "test2"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret B"}, {"idtGroupe", "idtLivretB"}, {"variables", "test2"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
    new Dictionary<string, string>{{"labelGroup", "Livret A"}, {"idtGroupe", "idtLivretA"}, {"variables", "test1"}},
};

我想有一本不带键“变量”的新字典，其中包含：

{"labelGroup", "Livret A"},
{"idtGroupe", "idtLivretA"},
{"labelGroup", "Livret B"},
{"idtGroupe", "idtLivretB"}

Answer 1

上面的答案很好，但是您可以使用一个简单的衬纸来完成。

        var distincts = test.SelectMany(x => x).Where(x=> x.Key != "variables").Distinct();

SelectMany（）将从您的词典中选择所有项目，然后加入一本词典

Distinct（）-简单的一个，它将选择不同的项目

Answer 2

您可以使用Distinct()方法。您必须在字典列表中迭代每个键。您的输出必须是字典列表，否则您将遇到重复的密钥问题。

            var distinctDictionary = new List<Dictionary<string, string>>();

            foreach (var keyItem in test.First().Keys)
            {
                if (keyItem == "variables")
                    continue;

                var tempDistinct = (from t in test select t[keyItem]).Distinct();

                foreach (var distinctItem in tempDistinct)
                {
                    distinctDictionary.Add(new Dictionary<string, string>() { { keyItem, distinctItem } });
                }
            }

如果测试词典为空，则First()方法将引发异常。您可能需要在迭代之前检查它是否为空。

如何在List <Dictionary <string，string >>上选择许多不同的元素？

2 个答案: