Question

我的任务是创建一个随机长度的A字母生成器。它必须创建50行字符串，其中包含随机数的A字母。老实说，我认为我真的很接近结论，但是，我仍然知道我缺少一些东西。目前，我的生成器正在创建随机数。

任务集中在使用for循环上。

此外-如果有比我编写的代码更容易编写我的代码的方法-我将不胜感激。

我尝试了另一种表达for循环的方式，但没有一个让我接近我的任务。

import java.util.*;
import java.lang.*;
import java.io.*;

class RandomGenerator{
    private static final String alpha = "a";
    private static final String data = alpha;

    private static final String combinationOFA = alpha;

    public static void main(String[] args) {


    for (int n=0; n<50; n++){
        Random theGeneratorForLength = new Random();
    }

    System.out.println("String : " + combinationOFA);
}

public static String generateRandomALetter(int length) {
Random theGeneratorAlpha = new Random();

StringBuilder sb = new StringBuilder(length);
for (int i = 0; i < length; i++) {

    int aLengthVariable = 
    theGeneratorAlpha.nextInt(combinationOFA.length());
    char alphaTeta = combinationOFA.charAt(aLengthVariable);

    sb.append(alphaTeta);
    }

return sb.toString();

}

}

我希望这段代码创建50个由随机长度乘以一个字母组成的字符串

Answer 1

也许这会有所帮助：

import java.util.*;

class RandomGenerator {
    private static final char A = 'A';

    public static void main(String[] args) {

        List<String> lines = new ArrayList<>();
        Random theGeneratorForLength = new Random();
        for (int n = 0; n < 50; n++) {
            int length = theGeneratorForLength.nextInt(50);
            char[] chars = new char[length];
            Arrays.fill(chars, A);
            String line = new String(chars);
            lines.add(line);
        }
        System.out.println("String : " + lines);
    }

}

Answer 2

像这样吗？

import java.util.*;
import java.lang.*;

class RandomGenerator {
    private static final String alpha = "a";
    private static final String data = alpha;

    // I removed final from here. reusing your string variable for storing values.
    private static String combinationOFA = alpha;

    // Introduced two variable max and min to find out max and min
    // characters you need to generate
    private static final Integer max = 50;
    private static final Integer min = 1;

    public static void main(String[] args) {

        for (int n = 0; n < 50; n++) {
            Random theGeneratorForLength = new Random();

            // you need to call method you created below with proper values.
            // min and max are max and min random values for you
            // and assigned value to combinationOFA
            combinationOFA = generateRandomALetter(theGeneratorForLength.nextInt(max - min) + min);

            // moved this line inside the loop to print
            System.out.println("String " + (n + 1) + " :" + combinationOFA);
        }
    }

    public static String generateRandomALetter(int length) {
        Random theGeneratorAlpha = new Random();

        StringBuilder sb = new StringBuilder(length);
        for (int i = 0; i < length; i++) {

            int aLengthVariable =
                    theGeneratorAlpha.nextInt(combinationOFA.length());
            char alphaTeta = combinationOFA.charAt(aLengthVariable);

            sb.append(alphaTeta);
        }
        return sb.toString();
    }
}

Answer 3

使用来自Apache Commons Lang lib的RandomStringUtils

public class RandomStringGenerator {
    public static void main(String [] args) {
        char[] charSet= {'a','b','c','d'};
        for(int i=0;i<50;i++){
            int length = (int)(Math.random()*100);
            System.out.println(RandomStringUtils.random(length,charSet));
        }
    }
}

Answer 4

public static void main(String[] args) {
    int maximumSymbolsInString = 50;
    int countOfStrings = 10;

    List<String> strings = new Random().ints(0, maximumSymbolsInString)
            .limit(countOfStrings)
            .mapToObj(el-> new String(new char[maximumSymbolsInString])
                                            .replace('\0', 'A')
                                            .substring(el))
            .collect(Collectors.toList());

    for (String string : strings) {
        System.out.println(string);
    }
}

在Java 11中，可以为每个字符串生成使用String类的新方法：repeate（int）。像"A".repeate(50)

Answer 5

我已经编写了带有循环的基本程序。这是您想要的输出吗？


import java.util.Random;

class RandomString {
   private static final String alpha = "a";

   public static void main(String[] args) {

       int length = 0;
       for (int n = 0; n < 50; n++) {
           Random l = new Random();
           length = l.nextInt(50) + 1;

           for (int i = 0; i < length; i++) {
               StringBuilder sb = new StringBuilder();
               sb = sb.append(alpha);
               System.out.print("String: "+sb.toString());

           }
           System.out.println();
       }
   }
}

如何创建包含多个单个字母的随机长度字符串？

5 个答案: