Question

我使用以下查询获取Laravel中的项目ID和特定表的ID。

$projectlist = Projects::Where('customer',$request->input('client_name'))->pluck(DB::raw("CONCAT('project_prefix','project_nos') AS projectid"),"id");

我收到了错误消息。

message Illegal offset type in isset or empty
exception   ErrorException
file    /var/www/msstone/vendor/laravel/framework/src/Illuminate/Support/Str.php

项目模型

namespace App;

use Illuminate\Database\Eloquent\Model;

class Projects extends Model
{
    protected $guarded = ['id'];

    protected $table = 'projects';

}

Answer 1

尝试通过更改雄辩的查询：

$projectlist=Projects::Where('customer',$request->input('client_name'))->pluck(DB::raw("CONCAT('project_prefix','project_nos') AS projectid"),"id");

到

$projectlist = Projects::select(DB::raw("CONCAT(project_prefix,project_nos) AS projectid"),'id')->where('customer',$request->input('client_name'))->pluck("projectid","id");

isset中的偏移量类型非法或Laravel空

1 个答案: