Question

我有一个字符串l1，例如包含以下内容：aackcdldccc。我想计算每个字符使用字典出现的次数。所需的最终结果应该是这样的字典：

a:2
c:5
k:1
d:2
l:1

如何修复我的代码，使其可以正常工作？我使用以下代码并收到错误消息：

l1= ('aackcdldccc')
print (l1)
d={}
print (len(l1))
for i in (range (len(l1))): 
        print (i)
        print (l1[i])
        print (list(d.keys()))
        if l1[i] in list(d.keys()):
            print ('Y')
            print (l1[i])
            print (list(d.keys())[l1[i]])
            d1 = {l1[i]:list(d.values())[l1[i]+1]}
            #print (d1)
            #d.update (d1)
        else:
            print ('N')
            d1={l1[i]:1}
            d.update (d1)

这是我得到的错误： aackcdldccc

11
0
a
[]
N
1
a
['a']
Y
a

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-185-edf313da1f8d> in <module>()
     10             print ('Y')
     11             print (l1[i])
---> 12             print (list(d.keys())[l1[i]])
     13             #d1 = {l1[i]:list(d.values())[l1[i]+1]}
     14             #print (d1)

TypeError: list indices must be integers or slices, not str

Answer 1

有两种方法可以做到这一点：

REPLACE( @[User::Variable],"\\","")

使用我的代码在python中将字符串转换为字典

1 个答案: