Question

我试图通过向下滚动在xpath中获取一个Webelement，但这很困难，因为该Webelement仅在向下滚动时出现，我的意思是此Webelement仅在向下滚动时出现，所以我不知道该怎么做，因为也许我必须先向下滚动一次，然后再向下滚动一次，直到出现我想要的网络元素为止，这取决于我要获得哪个元素。我尝试以此向下滚动，但没有从下方获取网络元素。

  JavascriptExecutor js = (JavascriptExecutor) getDriver();
        js.executeScript("window.scrollBy(0," + bajar + ")");
        waitFor(3).seconds();

我也尝试过此操作，但由于找不到WebElement而无法正常工作。

  Point loc = getDriver().findElement(findBy(String.format
            ("//div[@class='windowViewMode-maximized active lafPageHost']//tbody//td//span/a[@title='%s']//ancestor::tr//child::td//span/a[@title='%s']",
                    nombre_cuenta, accion_relacional))).getLocation();
    System.out.println(loc);
    JavascriptExecutor js = (JavascriptExecutor) getDriver();
    js.executeScript("javascript:window.scrollBy(0," + loc.y + ")");
    System.out.println("El valor de y es " +loc.y);
    System.out.println("Se hizo el scroll");
    waitFor(1).seconds();
    WebElement registroLista = findBy(String.format
            ("//div[@class='windowViewMode-maximized active lafPageHost']//tbody//td//span/a[@title='%s']//ancestor::tr//child::th//span/a[@title='%s']",
                    nombre_cuenta,accion_relacional));
    baseMetodosPagina.clickJavaScript(registroLista);

顺便说一下，我正在使用硒和Java。

Answer 1

未经测试，但类似的方法可能有效：

int LicksToTheCenterOfATootsiePop = 100;
int NumTries = 0;
int ec_Timeout = 10;

public void ScrollUntilElementFound(string xpath)
{
 try
  {
   wait = new WebDriverWait([your webdriver], ec_Timeout);
   List<WebElement> elements =  wait.until(ExpectedConditions.presenceOfAllElementsLocatedBy(By.xpath(xpath)));   
    if (elements.size() > 0) //may not need this, just return since timeout should be thrown if it's zero
       {
       return;
       }


   }
   catch (Exception ex)
   {
   NumTries++;
     if (NumTries<LicksToTheCenterOfATootsiePop)
        {
        ((JavascriptExecutor)[your webdriver]).executeScript("window.scroll(0, document.height);");
        ScrollUntilElementFound(xpath);
        }
     else 
        {
        return;
        }
    }
 }

ScrollUntilElementFound("[your XPATH to find Element]");
// now find element, and set NumTries back to zero if you plan on re-using

Answer 2

您可以尝试在网页上查找特定的Web元素。

JavascriptExecutor js = (JavascriptExecutor) getDriver();
js.executeScript("arguments[0].scrollIntoView(true);", web element locator);
//use explicit wait for synchronization purposes.

通过这种方式，您的页面将滚动到该Web元素，然后对所需的元素执行操作。

Answer 3

您需要滚动到该特定元素，并编写一个明确的等待条件，直到该元素可见为止，然后执行操作。这是示例代码：

import org.openqa.selenium.By;
import org.openqa.selenium.JavascriptExecutor;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;
import org.openqa.selenium.support.ui.ExpectedConditions;
import org.openqa.selenium.support.ui.WebDriverWait;

public class ScrollToElement{

public static void main(String[] args) {

    System.setProperty("webdriver.chrome.driver", "C:\\chromedriver.exe");
    WebDriver driver = new ChromeDriver();
    WebDriverWait w= new WebDriverWait(driver, 10);
    driver.get("https://semantic-ui.com/elements/button.html");
    driver.manage().window().maximize();

  // Scroll to specific Element

     JavascriptExecutor js=(JavascriptExecutor) driver;
     WebElement e = 
     driver.findElement(By.xpath("//button[contains(text(),'Negative')]"));
     js.executeScript("arguments[0].scrollIntoView();",e);
     w.until(ExpectedConditions.visibilityOf(e));


  }

}

Xpath Webelement仅在我向下滚动

3 个答案: