Question

美好的一天！如何正确地将FOR循环应用于给定函数？

感谢提示：）

from datetime import timedelta

from apps.tickets.models import PatientConsultationTicket


 def tickets_change():
     tickets = PatientConsultationTicket.object.all()
     one_day = tickets.created_at + timedelta(days=1)
     if datetime.now() > one_day:
         tickets.status = 'rd'
         tickets.save()
     elif datetime.now() < one_day:
         tickets.status = 'e'
         tickets.save()

Answer 1

要回答您的问题，那就是如何迭代门票：

from datetime import timedelta

from apps.tickets.models import PatientConsultationTicket


def tickets_change():
    tickets = PatientConsultationTicket.objects.all()
    for ticket in tickets:
        one_day = ticket.created_at + timedelta(days=1)
        if datetime.now() > one_day:
            ticket.status = 'rd'
            ticket.save()
        elif datetime.now() < one_day:
            ticket.status = 'e'
            ticket.save()

尽管如此，它可能不是您想要做的最好的方法。相反，您可能应该使用“ UPDATE”查询（未经测试，但看起来可能类似）：

PatientConsultationTicket.objects.filter(created_at__gte=datetime.now()-timedelta(days=1)).update(status='rd')
PatientConsultationTicket.objects.filter(created_at__lte=datetime.now()-timedelta(days=1)).update(status='e')

将FOR循环应用于函数

1 个答案: