Question

我整天有很多不同的时间，它们每隔15分钟上升一次。

Array
(
[0] => 12:00am
[1] => 12:15am
[2] => 12:30am
[3] => 12:45am
[4] => 1:00am
[5] => 1:15am
[6] => 1:30am
[7] => 1:45am
[8] => 2:00am
[9] => 3:15am
[10] => 3:30am
[11] => 3:45am
[12] => 4:00am
[13] => 1:00pm
[14] => 1:15pm
[15] => 1:30pm
);

我想做的是，按顺序将它们分组在一起，然后将它们放入另一个单独的数组中

因此，根据上述数组，我将像这样获得3个新数组

Array
(
[0] => 12:00am
[1] => 12:15am
[2] => 12:30am
[3] => 12:45am
[4] => 1:00am
[5] => 1:15am
[6] => 1:30am
[7] => 1:45am
[8] => 2:00am
);

12:00是主数组的开始，而2:00 am是模式停止的位置，因为下一个是3:15

array
{
[1] => 3:15am
[2] => 3:30am
[3] => 3:45am
[4] => 4:00am
)

3:15 am是主数组中新模式的开始，而4:00 am是模式停止的位置，依此类推。

我一直在尝试遍历主数组，并存储以前的时间以匹配当前的循环+ 15分钟，但是根本无法正常工作，感谢您的任何帮助，谢谢

Answer 1

谢谢@Wimanicesir

这只是逻辑和增强的代码

<?php
$input = Array
(
"12:00am",
"12:15am",
"12:30am",
"12:45am",
"1:00am",
"1:15am",
"1:30am",
"1:45am",
"2:00am",
"3:15am",
"3:30am",
"3:45am",
"4:00am",
"1:00pm",
"1:15pm",
"1:30pm",
);
$periods = [];
foreach($input as $time) {
    $hour = substr($time, 0, strpos($time, ':'));
    $partOfDay= substr($time, strlen($time) - 2);
    $index = ($hour== "12") ? "0" : floor($hour/2.00001);
    $periods[$index.":".$partOfDay][] = $time;
}
echo "<pre>";
var_dump($periods);
echo "</pre>";
exit();
?>

已编辑

按照OP的逻辑，我简化了逻辑，这是代码。

$periods = array();
$index = 0;
$old_value = 0;
foreach($input as $time) {
    //converting time to minutes
    $new_value = (intval(date("H",strtotime($time)))*60) + intval(date("i",strtotime($time)));
    if($new_value > ($old_value+15)){
        $index++;
    }
    $periods[$index][] = $time;
    $old_value = $new_value;
}

Answer 2

代码：

<?php
$times = [
    '12:00am',
    '12:15am',
    '12:30am',
    '12:45am',
    '1:00am',
    '1:15am',
    '1:30am',
    '1:45am',
    '2:00am',
    '3:15am',
    '3:30am',
    '3:45am',
    '4:00am',
    '1:00pm',
    '1:15pm',
    '1:30pm'
];

$previous = null;
$results = [[]];
foreach ($times as $time) {
    if (
        $previous === null ||
            (new \DateTime())->createFromFormat('h:ia', $time)->getTimestamp() -
            (new \DateTime())->createFromFormat('h:ia', $previous)->getTimestamp() === 15*60
    ) {
        $index = count($results)-1;
    } else {
        $index = count($results);
    }
    $results[$index][] = $time;
    $previous = $time;
}
echo "<pre>";
var_dump($results);
echo "</pre>";

输出（HTML视图）：

array(3) {
  [0]=>
  array(9) {
    [0]=>
    string(7) "12:00am"
    [1]=>
    string(7) "12:15am"
    [2]=>
    string(7) "12:30am"
    [3]=>
    string(7) "12:45am"
    [4]=>
    string(6) "1:00am"
    [5]=>
    string(6) "1:15am"
    [6]=>
    string(6) "1:30am"
    [7]=>
    string(6) "1:45am"
    [8]=>
    string(6) "2:00am"
  }
  [1]=>
  array(4) {
    [0]=>
    string(6) "3:15am"
    [1]=>
    string(6) "3:30am"
    [2]=>
    string(6) "3:45am"
    [3]=>
    string(6) "4:00am"
  }
  [2]=>
  array(3) {
    [0]=>
    string(6) "1:00pm"
    [1]=>
    string(6) "1:15pm"
    [2]=>
    string(6) "1:30pm"
  }
}

Answer 3

我制作了一个数组，将时间分为小时和上午/下午。这就是你想要的吗？

<?php
$input =
[ 
"12:00am", "12:15am", "12:30am", "12:45am",
"1:00am", "1:15am", "1:30am", "1:45am",
"2:00am", "3:15am", "3:30am", "3:45am",
"4:00am", "1:00pm", "1:15pm", "1:30pm",
];
// Prepare array
$periods = [];

// Loop all times in input
foreach($input as $time) {
    $hour = substr($time, 0, strpos($time, ':'));
    $partOfDay= substr($time, strlen($time) - 2);
    $periods[$hour][$partOfDay][] = $time;
}
var_dump($periods);

Answer 4

这里是功能：

<?php

$input = [
    "12:00am",
    "12:15am",
    "12:30am",
    "12:45am",
    "1:00am",
    "1:15am",
    "1:30am",
    "1:45am",
    "2:00am",
    // gap here
    "3:15am",
    "3:30am",
    "3:45am",
    "4:00am",
    // gap here
    "1:00pm",
    "1:15pm",
    "1:30pm",
];
$period = 15;

$result = split_periods($input, $period);

var_dump($result);

function split_periods($times, $period) {
    $standard_diff = $period * 60;
    $separated = [];
    $last_time = null;
    $n = 0;
    foreach ($times as $time) {
        $current_time = strtotime($time);
        if ($last_time) {
            $diff = $current_time - $last_time;
            if ($diff != $standard_diff) {
                ++$n;
            }
        }
        $separated[$n][] = $time;
        $last_time = $current_time;
    }

    return $separated;
}

为该函数提供时间数组，以及时间之间的期望间隔（以分钟为单位）。它返回一个数组数组，如下所示。

Array
(
    [0] => Array
        (
            [0] => 12:00am
            [1] => 12:15am
            [2] => 12:30am
            [3] => 12:45am
            [4] => 1:00am
            [5] => 1:15am
            [6] => 1:30am
            [7] => 1:45am
            [8] => 2:00am
        )

    [1] => Array
        (
            [0] => 3:15am
            [1] => 3:30am
            [2] => 3:45am
            [3] => 4:00am
        )

    [2] => Array
        (
            [0] => 1:00pm
            [1] => 1:15pm
            [2] => 1:30pm
        )

)

Answer 5

我使用strtotime（）将时间转换为unix时间戳，并计算与下一个元素的差异。

$arr = ['12:00am','12:15am','12:30am','12:45am','1:00am','1:15am','1:30am','1:45am','2:00am','3:15am','3:30am','3:45am','4:00am','1:00pm','1:15pm','1:30pm'];
$new = [];
$temp = [];
$total = count($arr);
for($i=0; $i< $total;$i++){
    $k = $i+1;
    //900 - it is 15 mins difference
    if(isset($arr[$k]) && strtotime($arr[$k]) - strtotime($arr[$i]) == 900){
        $temp[] = $arr[$i];
    }else{
        $temp[] = $arr[$i];
        $new[] = $temp;
        $temp = [];
    }
}
print_r($new);

Demo

如何获得数组中的第一个和最后一个时间序列

5 个答案: