Question

我写了一些小功能来快速浏览列表，字典等...

我现在发现以下代码很少出现行为

def main():

    Debug(['S',1,'G',False])

def Debug(Var,Name='noName'):
    Space ='  '
    if 'list' in type(Var).__name__:
        print('printing:',type(Var).__name__,Name,'\n')
        No=0
        for Item in Var:
            No += 1
            if 'str' in type(Item).__name__:
                print ( Space + Name + ' Item no.: ' + str(No) + ' {0:5s} <{1:s}>'.format( type(Item).__name__ , Item) )
                print ( Space + Name + ' Item no.: ' + str(No) + ' {0:5s} {1:s}' .format(type(Item).__name__,'<'+Item+'>'))
            else:
                print (Space + Name + ' Item no.: ' + str(No)+' {:5s}'.format(type(Item).__name__),Item)

        print('\n',type(Var).__name__,Name,'has',len(Var),'entries\n')
    return

输出为：

printing: list noName 

noName Item no.: 1 str     
noName Item no.: 1 str     
  noName Item no.: 2 int   1    
  noName Item no.: 3 str   <G>    
  noName Item no.: 3 str   <G>    
  noName Item no.: 4 bool  False

 list noName has 4 entries

有人知道为什么不打印'S'吗？甚至前面的空格都不见了...

Answer 1

请注意命名约定和isinstance的使用：

def debug(var, name='noName'):
    if isinstance(var, list):
        print('printing:', type(var), var, '\n')
        no = 0
        for index, item in enumerate(var): # enumerate gives us the index and the element
            if isinstance(item, str):
                print(f" {name} Item no.: {index + 1} {str(type(item)):5s} <{item:s}>")

            else:
                print(f" {name} Item no.: {index + 1} {str(type(item)):5s}")

        print(f'\n{str(type(var))} {name} has {len(var)} entries\n')

    return

if __name__ == '__main__':
    debug(['S',1,'G',False])

输出：

printing: <class 'list'> ['S', 1, 'G', False]

 noName Item no.: 1 <class 'str'> <S>
 noName Item no.: 2 <class 'int'>
 noName Item no.: 3 <class 'str'> <G>
 noName Item no.: 4 <class 'bool'>

<class 'list'> noName has 4 entries

输出问题打印

1 个答案: