我已经将当前时间戳转换为日期时间对象,并且能够减去它们。我的问题是我需要总结所有增量,但无法创建“空白”日期时间对象。例如0000-00-00 00:00:00.000
low_sum_time_alert_fired_to_closed = 0
low_sum_time_investigate_open_to_closed = 0
low_sum_time_alert_fired_to_investigation = 0
low_sum_time_alert_fired_to_first_assignment = 0
# iterate through the row index's
for idx in range(amt_of_rows):
# Index the row of the dataframe
row = df.iloc[idx]
vendor_name = row[2]
# formatting the timestamps
insert_at = datetime.strptime(row[3], "%Y-%m-%d %H:%M:%S.%f")
first_assignment = datetime.strptime(row[4], "%Y-%m-%d %H:%M:%S.%f")
first_investigated = datetime.strptime(row[5], "%Y-%m-%d %H:%M:%S.%f")
time_closed = datetime.strptime(row[6], "%Y-%m-%d %H:%M:%S.%f")
if row[0] == "LOW":
num_low += 1
####### THIS IS WHERE THINGS BREAK SINCE I'M TRYING TO ADD THE DIFFERENCE OF THE TIME STAMPS TO AN INTEGER ###
low_sum_time_alert_fired_to_closed += time_closed - insert_at
low_sum_time_investigate_open_to_closed += time_closed - first_investigated
low_sum_time_alert_fired_to_investigation += first_investigated - insert_at
low_sum_time_alert_fired_to_first_assignment += first_assignment - insert_at
low_sum_time_alert_fired_to_closed = low_sum_time_alert_fired_to_closed/amt_of_rows
low_sum_time_investigate_open_to_closed = low_sum_time_investigate_open_to_closed/amt_of_rows
low_sum_time_alert_fired_to_investigation = low_sum_time_alert_fired_to_investigation/amt_of_rows
low_sum_time_alert_fired_to_first_assignment = low_sum_time_alert_fired_to_first_assignment/amt_of_rows
答案 0 :(得分:0)
要汇总所有timedelta
,您需要从空白的timedelta
开始,而不是datetime
。
仅从datetime.timedelta(0)
开始。
简单的例子:
import datetime
td0 = datetime.timedelta(0)
td1 = datetime.timedelta(hours=1, minutes=1, seconds=1)
td2 = datetime.timedelta(hours=2, minutes=2, seconds=2)
td3 = datetime.timedelta(hours=3, minutes=3, seconds=3)
td0 += td1
td0 += td2
td0 += td3
print(td0)
输出:
6:06:06