我目前具有以下运行Bonus :: with('users')-> get()
时获得的数组结构我尝试添加数组并合并相似的键,但是它不起作用。我尝试使用laravel中提供的帮助程序方法,但似乎无法使其正常工作。
[
{
"id": 1,
"users_id": 1,
"bonus_type_id": 1,
"is_paid": 0,
"amount": "100.00",
"description": "desc",
"note": null,
"created_by": 2,
"last_modified_by": null,
"created_at": null,
"updated_at": null,
"deleted_at": null,
"user": {
"id": 1,
"name": "test",
"email": "test@testing.com",
"email_verified_at": null,
"status": 1,
"created_at": "2019-07-18 11:41:35",
"updated_at": "2019-07-18 11:41:35",
"deleted_at": null
}
},
{
"id": 2,
"users_id": 1,
"bonus_type_id": 2,
"is_paid": 0,
"amount": "100.00",
"description": "desc",
"note": null,
"created_by": 2,
"last_modified_by": null,
"created_at": null,
"updated_at": null,
"deleted_at": null,
"user": {
"id": 1,
"name": "test",
"email": "test@testing.com",
"email_verified_at": null,
"status": 1,
"created_at": "2019-07-18 11:41:35",
"updated_at": "2019-07-18 11:41:35",
"deleted_at": null
}
},
{
"id": 3,
"users_id": 2,
"bonus_type_id": 2,
"is_paid": 1,
"amount": "100.00",
"description": "desc",
"note": null,
"created_by": 2,
"last_modified_by": null,
"created_at": null,
"updated_at": null,
"deleted_at": null,
"user": {
"id": 1,
"name": "another test",
"email": "another@testing.com",
"email_verified_at": null,
"status": 1,
"created_at": "2019-07-18 11:41:35",
"updated_at": "2019-07-18 11:41:35",
"deleted_at": null
}
}
]
我希望结果像这样
[
{
user_id: 1,
name: "test",
bonuses: [
{
bonus_type_id: 1,
amount: 100,
is_paid: 0,
},
{
bonus_type_id: 2,
amount: 100,
is_paid: 0,
}
],
},
{
user_id: 2,
name: "another",
bonuses: [
{
bonus_type_id: 2,
amount: 100,
is_paid: 1,
},
]
}
]
答案 0 :(得分:0)
您需要改变雄辩的关系。在hasMany
模型中为奖金表定义bonuses
关系函数User
,并使用它来获得所需的结果,如下所示:
User::with('bonuses')->get();
这样,它将从用户表中返回结果并为每个用户填充奖励。
有意义吗?
答案 1 :(得分:0)
您可以通过选择子查询来获取特定信息,如果您的关系设置正确,这应该可以工作。
User::select('user_id','name','bonus_id')
->with(array('bonuses'=> function($query){
$query->select('bonus_type_id','amount','is_paid');
}))->get();