我有一个HTML辅助菜单,如下所示:
_Layout.cshtml
<div class="col nav-left h-100">
<p>Menu</p>
</div>
在我的 Site.js 中,我为切换设置了通用的JQuery函数:
var eventHandler = {
addToggle: function addToggle(btnElem, openEvent, closeEvent) {
const isClosedClass = 'this-is-closed';
btnElem.click(function () {
if ($(this).hasClass(isClosedClass)) {
openEvent();
} else {
closeEvent();
}
});
}
};
在我的 _Layout.cshtml 中,我这样调用此函数:
<script>
eventHandler.addToggle($(".btn-toggle-something"),
function () {
// Slide down
},
function () {
// Slide up
});
</script>
现在,我陷入了如何编写div上实际切换逻辑的问题。
如何使用通用功能切换侧面菜单?
我看过的来源:
答案 0 :(得分:1)
.slideUp()和.slideDown()与.toggleClass()结合使用-请参见以下内容:
var eventHandler = {
addToggle: function addToggle(btnElem, openEvent, closeEvent) {
const isClosedClass = 'this-is-closed';
btnElem.click(function () {
if ($(this).hasClass(isClosedClass)) {
openEvent();
} else {
closeEvent();
}
// Toggle `isClosedClass` for next time this is clicked.
btnElem.toggleClass(isClosedClass);
});
}
};
// Bind slideDown/slideUp.
var leftNav = $('.nav-left');
eventHandler.addToggle($('.btn-toggle-something'),
function () {
leftNav.slideDown();
},
function () {
leftNav.slideUp();
}
);
body {
margin: 0;
padding: 0;
}
p {
margin: 0;
}
.nav-left {
background-color: lightskyblue;
width: 200px;
height: 400px;
}
.btn-toggle-something {
cursor: pointer;
position: fixed;
top: 0;
left: 250px;
height: 50px;
width: 50px;
background-color: salmon;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="col nav-left h-100">
<p>Menu</p>
</div>
<div class="btn-toggle-something">Toggle</div>