Question

其中包括过程中的步骤以及每个步骤的状态。对于已完成的游行，“完成”步骤为最后一步，其持续时间为0 没有“完成”阶段的过程-它仍然继续运行查询我需要查询以在表中添加另一列，以计算过程中每个步骤的分钟数谢谢您的帮助哪种语法有效添加了表创建和数据的语法：

Create table T_Step (
    employee_ID INT
  , Process_ID  int
  , Step_ID     int
  , Start_Date  Datetime
  , Step_Status varchar(30)
);

Insert into T_Step values
    ('1','1','1','2018-01-01 8:00' ,'Pending')
  , ('1','1','2','2018-01-01 9:30' ,'InService')
  , ('1','1','3','2018-01-01 9:45' ,'Done')
  , ('2','2','1','2018-01-02 11:32','Pending')
  , ('2','2','2','2018-01-02 11:40','InService')
  , ('2','2','3','2018-01-02 12:20','Done')
;

谢谢

Answer 1

使用LEFT JOIN，然后为特定过程计算两步之间的时间差。

此查询适用于 MYSQL

select t1.employee_ID,t1.Process_ID,t1.Step_ID,t1.Start_Date,t1.Step_Status,
IFNULL(TIMESTAMPDIFF(MINUTE,t1.Start_Date,t2.Start_Date),0) As TimeInMinute
from T_Step t1
LEFT JOIN T_Step t2
ON t1.Process_ID=t2.Process_ID AND t1.Step_ID!=t2.Step_ID AND (t2.Step_ID-t1.Step_ID)=1
ORDER BY t1.Process_ID,t1.Step_ID;

输出

| employee_ID | Process_ID | Step_ID | Start_Date          | Step_Status | TimeInMinute |
| ----------- | ---------- | ------- | ------------------- | ----------- | ------------ |
| 1           | 1          | 1       | 2018-01-01 08:00:00 | Pending     | 90           |
| 1           | 1          | 2       | 2018-01-01 09:30:00 | InService   | 15           |
| 1           | 1          | 3       | 2018-01-01 09:45:00 | Done        | 0            |
| 2           | 2          | 1       | 2018-01-02 11:32:00 | Pending     | 8            |
| 2           | 2          | 2       | 2018-01-02 11:40:00 | InService   | 40           |
| 2           | 2          | 3       | 2018-01-02 12:20:00 | Done        | 0            |

DEMO

Answer 2

declare   @T_Step table  (
    employee_ID INT
  , Process_ID  int
  , Step_ID     int
  , Start_Date  Datetime
  , Step_Status varchar(30)
);

Insert into @T_Step values
    ('1','1','1','2018-01-01 8:00' ,'Pending')
  , ('1','1','2','2018-01-01 9:30' ,'InService')
  , ('1','1','3','2018-01-01 9:45' ,'Done')
  , ('2','2','1','2018-01-02 11:32','Pending')
  , ('2','2','2','2018-01-02 11:40','InService')
  , ('2','2','3','2018-01-02 12:20','Done')
;

with cte as (Select *, R=ROW_NUMBER()
            over(partition by employee_ID order by employee_ID)
            from @T_Step)

Select T1.employee_ID,T1.Process_ID,T1.Step_Status,t1.Start_Date,t2.Start_Date, DATEDIFF(SECOND,t2.Start_Date,t1.Start_Date) TimeTaken
from cte T1
    left join cte T2 on T1.R = T2.R+1 and T1.employee_ID = T2.employee_ID
order by T1.employee_ID

计算每个步骤的过程-在SQL中

2 个答案: