Question

我想更改下一个和上一个箭头。但是innerHTML不会影响<th class="next">>></th>。我该怎么办？

$(".datepicker").datepicker();

<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.9.0/css/bootstrap-datepicker.min.css">

<input type="text" class="datepicker">

<script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.9.0/js/bootstrap-datepicker.min.js"></script>

Answer 1

您可以这样更改图标：

$(document).ready(function(){
    $(".datepicker").datepicker().on('show', function(e){
       $('.prev').text('<<<');
  		$('.next').text(">>>");
    });
});

<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.9.0/css/bootstrap-datepicker.min.css">
<script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.9.0/js/bootstrap-datepicker.min.js"></script>

<input type="text" class="datepicker">

Answer 2

这是另一个仅使用 CSS 的想法。

$(".datepicker").datepicker();

.table-condensed > thead > tr:nth-child(2) > .prev {
  font-size: 0;
  background: url("data:image/svg+xml,%0A%3Csvg xmlns='http://www.w3.org/2000/svg' width='24' height='24' viewBox='0 0 24 24' fill='none' stroke='currentColor' stroke-width='2' stroke-linecap='round' stroke-linejoin='round' %3E%3Cline x1='19' y1='12' x2='5' y2='12'%3E%3C/line%3E%3Cpolyline points='12 19 5 12 12 5'%3E%3C/polyline%3E%3C/svg%3E") 50% 50% / contain no-repeat;
}

.table-condensed > thead > tr:nth-child(2) > .next {
  font-size: 0;
  background: url("data:image/svg+xml, %3Csvg xmlns='http://www.w3.org/2000/svg' width='24' height='24' viewBox='0 0 24 24' fill='none' stroke='currentColor' stroke-width='2' stroke-linecap='round' stroke-linejoin='round' %3E%3Cline x1='5' y1='12' x2='19' y2='12'%3E%3C/line%3E%3Cpolyline points='12 5 19 12 12 19'%3E%3C/polyline%3E%3C/svg%3E") 50% 50% / contain no-repeat;
}

<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.9.0/css/bootstrap-datepicker.min.css">

<input type="text" class="datepicker">

<script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.9.0/js/bootstrap-datepicker.min.js"></script>

使用遮罩更改图标的颜色：（您已经可以通过更改填充或描边颜色来更改 SVG 的颜色，但假设您使用的是 PNG 而不是 SVG）

$(".datepicker").datepicker();

.table-condensed > thead > tr:nth-child(2) > .prev {
  font-size: 0;
  --mask: url("data:image/svg+xml,%0A%3Csvg xmlns='http://www.w3.org/2000/svg' width='24' height='24' viewBox='0 0 24 24' fill='none' stroke='currentColor' stroke-width='2' stroke-linecap='round' stroke-linejoin='round' %3E%3Cline x1='19' y1='12' x2='5' y2='12'%3E%3C/line%3E%3Cpolyline points='12 19 5 12 12 5'%3E%3C/polyline%3E%3C/svg%3E") 50% 50% / contain no-repeat;
  -webkit-mask: var(--mask);
          mask: var(--mask);
   background: red;
}

.table-condensed > thead > tr:nth-child(2) > .next {
  font-size: 0;
  --mask: url("data:image/svg+xml, %3Csvg xmlns='http://www.w3.org/2000/svg' width='24' height='24' viewBox='0 0 24 24' fill='none' stroke='currentColor' stroke-width='2' stroke-linecap='round' stroke-linejoin='round' %3E%3Cline x1='5' y1='12' x2='19' y2='12'%3E%3C/line%3E%3Cpolyline points='12 5 19 12 12 19'%3E%3C/polyline%3E%3C/svg%3E") 50% 50% / contain no-repeat;
  -webkit-mask: var(--mask);
          mask: var(--mask);
   background: blue;
}

<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.9.0/css/bootstrap-datepicker.min.css">

<input type="text" class="datepicker">

<script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.9.0/js/bootstrap-datepicker.min.js"></script>

Answer 3

您需要遍历上一个和下一个类并更改内部HTML

$（“。prev”）。each（function（i）{$（“。prev”）[i] .innerHTML =“ your icon”}）

如何更改Bootstrap Datepicker图标？

3 个答案: