如何在SQL Server中使用解析名称分隔值

Question

我的值为（500，850，65.5）为GivenUnitPrice，我想通过用PARSENAME来分隔各个列来分隔这些值

我已经尝试过

PARSENAME(GivenUnitPrice, 3) as DB,
        PARSENAME(GivenUnitPrice, 2) as Owner,
        PARSENAME(GivenUnitPrice, 1) as Object

结果是

DB   |     Owner      |      Object
NULL | 500 , 850 , 65 |       5

Answer 1

 DECLARE @GivenUnitPrice VARCHAR(100)= '500 , 850 , 65.5' 

 SELECT PARSENAME(replacE(@GivenUnitPrice,',','.'),4)  as DB,PARSENAME(replacE(@GivenUnitPrice,',','.'),3)  as Owner,PARSENAME(replacE(@GivenUnitPrice,',','.'),2)+ '.'+PARSENAME(@GivenUnitPrice,1) AS OBJECT

Answer 2

您可以尝试这个。...

DECLARE @UnitPrice VARCHAR(100)

SET  @UnitPrice= '500 , 850 , 65.5' 

SELECT PARSENAME(REPLACE(@UnitPrice,',','.'),4)  as DB,

PARSENAME(REPLACE(@UnitPrice,',','.'),3)  as Owner,

PARSENAME(REPLACE(@UnitPrice, ',', '.'), 2) AS OBJECT,

PARSENAME(REPLACE(@UnitPrice, '', '.'), 1) AS OBJECT

Answer 3

PARSENAME基本上将。（Dot）视为字符串中的分号。在您的输入字符串中，末尾只有一个。（点），因此您只能在“所有者”和“对象”列中获取值。如果要对此字符串使用PARSENAME，请先用。（点）替换逗号，然后按如下所示应用PARSENAME-

DECLARE @ObjectName NVARCHAR(1000);
SET @ObjectName = '500 , 850 , 65.5';
SET @ObjectName = REPLACE(@ObjectName, ',', '.');

SELECT PARSENAME(@ObjectName, 4) AS Server, 
       PARSENAME(@ObjectName, 3) AS DB, 
       PARSENAME(@ObjectName, 2) AS Owner, 
       PARSENAME(@ObjectName, 1) AS Object;

Answer 4

您似乎想用逗号分隔字符，但是Parsename()函数用点字符分隔（例如，十进制数65.5也像分隔整数一样被分隔），因此对您的结果产生错误的结果案件。最好将replace()，substring()和charindex()一起使用：

with t as
(
select replace(replace('500 , 850 , 65.5',')',''),'(','') as GivenUnitPrice 
), t2 as
(
 select substring(GivenUnitPrice,1,charindex(',',GivenUnitPrice)-1) as db,
        substring(GivenUnitPrice,charindex(',',GivenUnitPrice)+1,len(GivenUnitPrice)) as owner_object       
   from t
)    
select db,
       substring(owner_object,1,charindex(',',owner_object)-1) as owner,
       substring(owner_object,charindex(',',owner_object)+1,len(owner_object)) as object
  from t2;

 db  owner  object
 500  850    65.5

Demo