Question

我想编写一个SQL查询以获取下面给出的问题解决方案-我有一个类似这样的表：

CREATE TABLE order 
(
    id INT,
    name VARCHAR(255),
    income INT,
    order_date DATE
)

如果查询有问题，请原谅。

现在，我希望sql查询给出的结果是2017年用户的总收入，该用户的第一笔订单创建于2016年。

Answer 1

您的订单表似乎是个奇怪的设计，但是给定了

drop table if exists t;
create table t
(
    id INT,
    name VARCHAR(255),
    income INT,
    order_date DATE
);

insert into t values
(1,'aaa',10,'2016-01-01'),(1,'aaa',10,'2017-01-01'),(1,'aaa',10,'2017-01-01'),
(2,'bbb',10,'2015-01-01'),(2,'bbb',10,'2016-01-01'),(2,'bbb',10,'2017-01-01'),
(3,'ccc',10,'2017-01-01'),(3,'ccc',10,'2017-01-01'),(3,'ccc',10,'2018-01-01')
;

一个简单的联接可能就是您所需要的

select t.name,sum(t.income)
from t
join (select name,min(year(order_date)) minyr from t  group by name) s 
        on t.name = s.name
where year(order_date) = 2017 and minyr = 2016
group by name;

+------+---------------+
| name | sum(t.income) |
+------+---------------+
| aaa  |            20 |
+------+---------------+
1 row in set (0.00 sec)

Answer 2

SELECT id, name, SUM(income) 
    FROM [order] 
    WHERE DATEPART(yyyy,order_date)='2017'
    AND id IN (SELECT id FROM [order] GROUP BY id HAVING MIN(DATEPART(yyyy,order_date)) ='2016')
    GROUP BY id, name

SQL查询记录

2 个答案: