Question

我有外部API，代理人休息了，读者定义的类型：“ json”， rootProperty：'数据;

如何获取属性“ FullName” 我已经尝试过record.get（'FullName'）。

创建的名为getDetails的函数，作为参数字符串传递，返回返回record.get（'FullName），始终未定义。

 Details: function(v, record) {

       return record.get('FullName') 
    }

这是onDelete函数：

OnDelete: function (record,data) {
     Ext.Msg.confirm('Delete Changes', 'Do you want to delete' + " " + record.Details, function (choice) {

            if (choice === 'yes') {
                var store = Ext.getStore('store.Personnel');
                store.remove(record);
                store.sync();

            }
        })
    },

this is how console log on record look like. I have 3 constructors with Id's then data, and then obj properties）

Answer 1

您应使用record.get（'FullName'）之类的

OnDelete: function (grid, rowId) {
    var record = grid.getStore().getAt(rowId);
        Ext.Msg.confirm('Delete Changes', 'Do you want to delete' + " " + record.get('FullName'), function (choice) {
            if (choice === 'yes') {
                var store = grid.getStore();
                console.log(store)
                store.remove(record);

            }
        })
    }

您的小提琴示例：https://fiddle.sencha.com/#view/editor&fiddle/2ttb

如何访问对象属性

1 个答案: