我需要一个正则表达式来匹配用双引号引起来的字符串。如果此模式用单引号引起来,则它不应与用双引号引起来的字符串匹配:
"string"
" 'xyz' "
" `" "
" `" `" "
" `" `" `" "
' ' "should match" ' '
' "should not match" '
现在我有(https://regex101.com/r/z5PayV/1)
(?:"(([^"]*`")*[^"]*|[^"]*)")
匹配所有行。但是最后一行不应该匹配。有解决办法吗?
答案 0 :(得分:3)
您必须经过单引号才能将其排除在匹配范围之外
更新
对于C#,必须像这样完成。
只需使用简单的CaptureCollection即可获取所有内容
引用的匹配项。
(?:'[^']*'|(?:"(([^"]*`")*[^"]*|[^"]*)")|[\S\s])+
扩展
(?:
' [^']* '
|
(?:
"
( # (1 start)
( [^"]* `" )* # (2)
[^"]*
| [^"]*
) # (1 end)
"
)
|
[\S\s]
)+
C#代码
var str =
"The two sentences are 'He said \"Hello there\"' and \"She said 'goodbye' and 'another sentence'\"\n" +
"\" `\" \"\n" +
"\" `\" \"\n" +
"\" `\" `\" \"\n" +
"\" `\" `\" `\" \"\n" +
"' \" \" '\n" +
"\"string\"\n" +
"\" 'xyz' \"\n" +
"\" `\" \"\n" +
"\" `\" `\" \"\n" +
"\" `\" `\" `\" \"\n" +
"' ' \"should match\" ' '\n" +
"' \"should not match\" '\n";
var rx = new Regex( "(?:'[^']*'|(?:\"(([^\"]*`\")*[^\"]*|[^\"]*)\")|[\\S\\s])+" );
Match M = rx.Match( str );
if (M.Success)
{
CaptureCollection cc = M.Groups[1].Captures;
for (int i = 0; i < cc.Count; i++)
Console.WriteLine("{0}", cc[i].Value);
}
输出
She said 'goodbye' and 'another sentence'
`"
`"
`" `"
`" `" `"
string
'xyz'
`"
`" `"
`" `" `"
should match
对不起,这是在PCRE引擎中完成的方式
'[^']*'(*SKIP)(*FAIL)|(?:"(([^"]*`")*[^"]*|[^"]*)")`
https://regex101.com/r/gMiVDU/1
' [^']* '
(*SKIP) (*FAIL)
|
(?:
"
( # (1 start)
( [^"]* `" )* # (2)
[^"]*
| [^"]*
) # (1 end)
"
)
___________________________-
答案 1 :(得分:0)
答案看起来很复杂,这是怎么回事:
^“(\ d + | \ D +)” $
这太简单了吗?
这里的想法是检查字符串的开头和结尾是否带有双引号(“),双引号内的任何内容(包括单引号)都是允许的。