Question

我希望总结本月和上个月的数据。我的桌子看起来像这样：

Date        Client  Amount
2019-06-02  111     100
2019-06-03  111      90
2019-06-22  222      80
2019-07-02  111     110
2019-07-03  111     120

预期结果：

Client   This_month    Previous_month
111      230           190           
222                    80

感谢您提供任何操作提示。

Answer 1

您可以group by client并使用条件聚合：

select
  client,
  sum(case when last_day(date) = last_day(current_date) then amount end) This_month,
  sum(case when last_day(date) = last_day(current_date - INTERVAL 1 MONTH) then amount end) Previous_month    
from tablename
group by client

请参见demo。
结果：

| client | This_month | Previous_month |
| ------ | ---------- | -------------- |
| 111    | 230        | 190            |
| 222    |            | 80             |

Answer 2

您可以尝试使用一对左联接

select  a.Client, b.act_amount, c.prev_amount
from (
    select distinct client 
    from my_table
) a
left join (
    select month(date) act_mont, client, sum(amount) act_amount
    from my_table 
    where month(date) = month(curdate)
    group by month(date), client
) b on a.client = b.client 
left join (
    select month(date) prev_mont, client, sum(amount) prev_amount
    from my_table 
    where month(date) = month(curdate) -1
    group by month(date), client
) c on a.client = c.client

从一个表中按当月和上月汇总数据

2 个答案: