Question

我必须使用sorted方法和lambda在python中对有序字典进行排序。我按键排序，键是字符串这是我拥有的字典代码：

sensors = OrderedDict()
sensors['4213'] = ("STEM Center", 0)
sensors['4201'] = ("Foundations Lab ", 1)
sensors['4204'] = ("CS Lab ", 2)
sensors['4218'] = ("Workshop Room ", 3)
sensors['4205'] = ("Tiled Room ", 4)
sensors['Out'] = ("Outside ", 5)

我该如何对它进行排序，以便首先显示4201，然后增加数字，然后显示最后一个，出来？

我尝试实现它以及它的变体，但是它不起作用，元素的顺序保持不变

OrderedDict(sorted(sensors.items(), key=lambda x: x[0])

变化：

-sorted(sensors.items(), key=lambda x: x[0])
-creating a regular dictionary called sensors and then making a new ordered dictionary using OrderedDict(sorted(sensors.items(), key=lambda x: x[0])

谢谢！

Answer 1

OrderedDict中的键顺序等于插入顺序。要对其进行排序，请按期望的顺序从头开始创建一个新的

。

import collections

# source does not have to be sorted, a regular dict will do
sensors = {}
sensors['4213'] = ("STEM Center", 0)
sensors['4201'] = ("Foundations Lab ", 1)
sensors['4204'] = ("CS Lab ", 2)
sensors['4218'] = ("Workshop Room ", 3)
sensors['4205'] = ("Tiled Room ", 4)
sensors['Out'] = ("Outside ", 5)

sorted_keys = sorted(sensors)     # key=... optional
sorted_sensors = collections.OrderedDict((key, sensors[key]) for key in sorted_keys)

使用Lamba对OrderedDict排序

1 个答案: