我想将hyper与bb8和tokio-postgres一起使用。在每个请求中,我都希望从池中获取一个新的连接。有人可以为我提供一些这种情况的例子吗? 目前我是这样的:
fn main() {
let addr = "127.0.0.1:3000".parse().unwrap();
let pg_mgr =
PostgresConnectionManager::new("postgresql://auth:auth@localhost:5433/auth", NoTls);
rt::run(future::lazy(move || {
Pool::builder()
.build(pg_mgr)
.map_err(|e| eprintln!("Database error: {}", e))
.and_then(move |pool| {
let service = || service_fn(|req| router(req, pool.clone()));
let server = Server::bind(&addr)
.serve(service)
.map_err(|e| eprintln!("Server error: {}", e));
println!("Listening on http://{}", addr);
server
})
}))
}
fn router(
_req: Request<Body>,
_pool: Pool<PostgresConnectionManager<NoTls>>,
) -> Result<Response<Body>, hyper::Error> {
// do some staff with pool
}
但是它不会编译:
error[E0597]: `pool` does not live long enough
--> src/main.rs:22:63
|
22 | let service = || service_fn(|req| router(req, pool.clone()));
| -- -----------------------------^^^^----------
| | | |
| | | borrowed value does not live long enough
| | returning this value requires that `pool` is borrowed for `'static`
| value captured here
...
30 | })
| - `pool` dropped here while still borrowed
我在做什么错?如何使我的案件正常工作?
答案 0 :(得分:2)
解决方案非常简单,但是要了解这个问题,我想提供一些其他信息...
当您将来调用and_then
以获得结果时,它将变量的值传递到传递给and_then
的闭包中,从而使您拥有该数据的所有权。
hypers构建器上的方法serve
(由Server::bind
返回)期望闭包具有静态寿命。
现在要解决该问题:
service_fn
是在and_then
闭包之外定义的,因此该函数的寿命足够长了service_fn
。要解决此问题,只需将move
本地数据放入闭包中,如下所示:
let service = move || service_fn(|req| router(req, pool));
答案 1 :(得分:0)
找到解决办法here
最简单的解决方案如下:
fn main() {
let addr = "127.0.0.1:3000".parse().unwrap();
let pg_mgr =
PostgresConnectionManager::new("postgresql://auth:auth@localhost:5433/auth", NoTls);
rt::run(future::lazy(move || {
Pool::builder()
.build(pg_mgr)
.map_err(|_| eprintln!("kek"))
.and_then(move |pool| {
let service = move || {
let pool = pool.clone();
service_fn(move |req| router(req, &pool))
};
let server = Server::bind(&addr)
.serve(service)
.map_err(|e| eprintln!("Server error: {}", e));
println!("Listening on http://{}", addr);
server
})
}))
}
fn router(
_req: Request<Body>,
_pool: &Pool<PostgresConnectionManager<NoTls>>,
) -> impl Future<Item = Response<Body>, Error = hyper::Error> {
// some staff
}
还可以使用service
和rt::run
在Arc
之外构造Mutex
:
fn main() {
let addr = "127.0.0.1:3000".parse().unwrap();
let pg_mgr =
PostgresConnectionManager::new("postgresql://auth:auth@localhost:5433/auth", NoTls);
let pool: Arc<Mutex<Option<Pool<PostgresConnectionManager<NoTls>>>>> =
Arc::new(Mutex::new(None));
let pool2 = pool.clone();
let service = move || {
let pool = pool.clone();
service_fn(move |req| {
let locked = pool.lock().unwrap();
let pool = locked
.as_ref()
.expect("bb8 should be initialized before hyper");
router(req, pool)
})
};
rt::run(future::lazy(move || {
Pool::builder()
.build(pg_mgr)
.map_err(|_| eprintln!("kek"))
.and_then(move |pool| {
*pool2.lock().unwrap() = Some(pool);
let server = Server::bind(&addr)
.serve(service)
.map_err(|e| eprintln!("Server error: {}", e));
println!("Listening on http://{}", addr);
server
})
}))
}
fn router(
_req: Request<Body>,
_pool: &Pool<PostgresConnectionManager<NoTls>>,
) -> impl Future<Item = Response<Body>, Error = hyper::Error> {
// some staff
}