C#-设置HttpClient标头以将数据发布到Azure REST API

时间:2019-07-17 13:02:46

标签: c# azure httpclient

我正在尝试将一些数据发布到Azure REST API。我在Postman中定义了一个有效的请求。现在,在我的C#代码中,我想使用HttpClient而不是帮助程序库。为了做到这一点,我目前有:

try
{
  var json = @"{
    '@search.action':'upload',
    'id':'abcdef',
    'text':'this is a long blob of text'
  }";

  using (var client = new HttpClient())
  {
    var requestUri = $"https://my-search-service.search.windows.net/indexes/my-index/docs/index?api-version=2019-05-06";

    // Here is my problem
    client.DefaultRequestHeaders.Clear();
    client.DefaultRequestHeaders.Add("api-key", myKey);
    client.DefaultRequestHeaders.Add("Content-Type", "application/json");

    using (var content = new StringContent(json, Encoding.UTF8, "application/json")
    {
      using (var request = Task.Run(async() => await client.PostAsync(requestUri, content)))
      {
        request.Wait();
        using (var response = request.Result)
        {
        }
      }
    }
  }
}
catch (Exception exc)
{
  Console.WriteLine(exc.Message);
}

运行此命令时,会抛出一个InvalidOperationException,内容为:

Misused header name. Make sure request headers are used with HttpRequestMessage, response headers with HttpResponseMessage, and content headers with HttpContent objects.

我不明白自己做错了什么。如何使用C#中的HttpClient将数据发布到Azure REST API?

谢谢!

4 个答案:

答案 0 :(得分:1)

内容类型是内容的标头,而不是请求的标头,这就是失败的原因。您还可以在创建请求的内容本身时设置内容类型(请注意,代码段在两个位置(用于Accept和Content-Type标头)添加了“ application / json”)

client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));//ACCEPT

答案 1 :(得分:0)

您看到这个tuto吗?

初始化HttpCLient

HttpClient client = new HttpClient();
client.BaseAddress = new Uri("http://localhost:64195/");
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(
        new MediaTypeWithQualityHeaderValue("application/json"));

发布您的对象

Product product = new Product
{
            Name = "Gizmo",
            Price = 100,
            Category = "Widgets"
};    
var url = await CreateProductAsync(product);

static async Task<Uri> CreateProductAsync(Product product)
{
    HttpResponseMessage response = await client.PostAsJsonAsync(
        "api/products", product);
    response.EnsureSuccessStatusCode();

    // return URI of the created resource.
    return response.Headers.Location;
}

答案 2 :(得分:0)

如果要添加任何标题,请使用此

 var apiClient = new HttpClient()
                    {
                      BaseAddress = new Uri(apiBaseURL)
                    };

var request = new HttpRequestMessage(HttpMethod.Post, "/api/controller/method");
request.Headers.Add("Accept", "application/json");
request.Headers.Add("api-key", mykey);
request.Content = new StringContent(json, Encoding.UTF8, "application/json");

var response = apiClient.SendAsync(request).Result;
response.EnsureSuccessStatusCode();

答案 3 :(得分:0)

尝试一下:

content.Headers.ContentType = new MediaTypeHeaderValue("application/json");