Question

我确实需要在这里进行逻辑的帮助，因此我在UIPickerView中使用了3个不同的数组。当用户在pickerview中选择类似的内容时，应执行某个公式（它不相关）是的我应该使用什么？如果陈述？开关？还有一个问题。用作字符串的shiftCount数组数据会出现问题吗？因为我需要将公式乘以* 1或* 2等。

   var shiftCount = [
   "1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25"]

   var Level = [
       "White","Silver 80%","Silver 100%","Gold 80%","Gold 100%","Diamond 80%","Diamond 100%",]

   var shiftDay = [

   "MNG","LMNG","AFT","LAFT","PEAK","LNGT","NGT"]

func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {


        switch (component) {
        case 0:
            MyShifts = shiftCount[row]
            shifts.text = "How many shifts: " + MyShifts
            print(MyShifts)
        case 1:
            MyShiftType = shiftDay[row]
            shiftType.text = "Shift you work: " + MyShiftType
            print(MyShiftType)
        case 2:
            MyLevel = Level[row]
            level.text = "Your Level: " + MyLevel
            print(MyLevel)
        default:
            break
        }

Answer 1

如果只有两个要评估的选项，建议使用if语句，因此在这种情况下，使用switch语句就可以了，关于第二个关于字符串数组的问题，当您要应用公式时就不会有问题是一个问题，但是您需要将该字符串转换为Int，Double，Float或任何类型，您需要进行数学计算，并且如果您想在标签或类似的东西上进行显示，则可以进行字符串插值显示它。

条件或是否在pickerview中的语句

1 个答案: