Question

我要从总时隙中删除预订的时隙，我该怎么做？

输入：

实际时隙：

[ '10:00-10:30',
  '10:30-11:00',
  '11:00-11:30',
  '11:30-12:00',
  '12:00-12:30',
  '12:30-13:00',
  '13:00-13:30',
  '13:30-14:00',
  '14:00-14:30',
  '14:30-15:00',
  '15:00-15:30',
  '15:30-16:00'
]

如果预订时隙为["11:00-13:00","14:00-15:00"]，则输出应为：

 [{
    "slot": "10:00-10:30",
    "isBooked": false
},
{
    "slot": "10:30-11:00",
    "isBooked": false
},
{
    "slot": "11:00-11:30",
    "isBooked": true
},
{
    "slot": "11:30-12:00",
    "isBooked": true
},
{
    "slot": "12:00-12:30",
    "isBooked": true
},
{
    "slot": "12:30-13:00",
    "isBooked": true
},
{
    "slot": "13:00-13:30",
    "isBooked": false
},
{
    "slot": "13:30-14:00",
    "isBooked": false
},
{
    "slot": "14:00-14:30",
    "isBooked": true
},
{
    "slot": "14:30-15:00",
    "isBooked": true
},
{
    "slot": "15:00-15:30",
    "isBooked": false
},
{
    "slot": "15:30-16:00",
    "isBooked": false
}]

如果预订时隙为["11:15-13:15"]，则输出应为：

 [{
    "slot": "10:00-10:30",
    "isBooked": false
},
{
    "slot": "10:30-11:00",
    "isBooked": false
},
{
    "slot": "11:00-11:30",
    "isBooked": true
},
{
    "slot": "11:30-12:00",
    "isBooked": true
},
{
    "slot": "12:00-12:30",
    "isBooked": true
},
{
    "slot": "12:30-13:00",
    "isBooked": true
},
{
    "slot": "13:00-13:30",
    "isBooked": false
},
{
    "slot": "13:30-14:00",
    "isBooked": false
},
{
    "slot": "14:00-14:30",
    "isBooked": false
},
{
    "slot": "14:30-15:00",
    "isBooked": false
},
{
    "slot": "15:00-15:30",
    "isBooked": false
},
{
    "slot": "15:30-16:00",
    "isBooked": false
}]

我已经尝试过了：

 let actualTimeSlot = []
                                for(let i = 0; i < times_ara.length; i++) {
                                    if(parseInt(times_ara[i]) < parseInt(timeBooked.split("-")[0])){
                                        actualTimeSlot.push(times_ara[i])
                                    } else if(parseInt(times_ara[i]) > parseInt(timeBooked.split("-")[1])) {
                                        actualTimeSlot.push(times_ara[i])
                                    } else {
                                        console.log("booked")
                                    }
                                }

但不适用于所有情况

我已经更新了输出，上一个工作正常。只是需要有关更新的更多帮助。

Answer 1

您可以尝试以下方法将时隙数组map()变成对象数组：

const ts = ['10:00-10:30','10:30-11:00','11:00-11:30','11:30-12:00','12:00-12:30','12:30-13:00','13:00-13:30','13:30-14:00','14:00-14:30','14:30-15:00','15:00-15:30','15:30-16:00'];

const booked3 = ["11:00-11:30", "13:05-13:35", "14:05-14:15"];

const avail = (ts, booked) =>
	ts.map(item => {
		const[start, end] = item.split('-');
		const isBooked = booked
			.map(item => item.split('-'))
			.some(([bookedStart, bookedEnd]) =>
				(start >= bookedStart && start < bookedEnd) ||
				(end > bookedStart && end <= bookedEnd) ||
				(bookedStart >= start && bookedStart < end));
		return {slot: `${start}-${end}`, isBooked};
	})
    


console.log(avail(ts,booked3));

.as-console-wrapper {min-height: 100%}

Answer 2

您可以检查该值是在间隔内还是在两端之一。

function remove(from, slots) {
    return slots.reduce((r, s) => {
        var [sStart, sEnd] = s.split('-');
        return r.filter(f => {
            var [fStart, fEnd] = f.split('-');
            return (fStart < sStart || fEnd > sEnd) && (fStart > sStart || fEnd <= sStart) && (fStart >= sEnd || fEnd < sEnd);
        });
    }, from);
}

var array = ['10:00-10:30', '10:30-11:00', '11:00-11:30', '11:30-12:00', '12:00-12:30', '12:30-13:00', '13:00-13:30', '13:30-14:00', '14:00-14:30', '14:30-15:00', '15:00-15:30', '15:30-16:00'],
    result1 = remove(array, ["11:00-13:00", "14:00-15:00"]),
    result2 = remove(array, ["11:15-13:15"]);

console.log(result1);
console.log(result2);

.as-console-wrapper { max-height: 100% !important; top: 0; }

从时隙中删除预订的时间

2 个答案: