Question

在我的应用程序中，我可以选择让用户打开设置并允许位置。导航到设置屏幕后，如何知道用户打开了该位置？这是启动设置活动的方式。

if(!gps_enabled && !network_enabled) {
            // notify user
            new AlertDialog.Builder(this)
                    .setMessage(R.string.gps_network_not_enabled)
                    .setPositiveButton(R.string.open_location_settings, new DialogInterface.OnClickListener() {
                        @Override
                        public void onClick(DialogInterface paramDialogInterface, int paramInt) {
                            startActivityForResult(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS), isGpsTurnedOnResult );
                        }
                    }).setNegativeButton(R.string.Cancel,null)
                    .show();
        }

这是我尝试获得结果的方法：

 @Override
    protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
    }

当我检查data时发现它为空，是否有办法知道用户打开了该位置？当然，我可以使用LocationManager进行检查，但这不是我想要的解决方案，除非这是唯一可行的方法。

Answer 1

构建位置设置

LocationSettingsRequest.Builder builder = new LocationSettingsRequest.Builder()
     .addLocationRequest(locationRequest);

LocationSettingsRequest.Builder builder = new LocationSettingsRequest.Builder();

// ...

SettingsClient client = LocationServices.getSettingsClient(this);
Task<LocationSettingsResponse> task = client.checkLocationSettings(builder.build());

提示用户更改位置设置

task.addOnSuccessListener(this, new OnSuccessListener<LocationSettingsResponse>() {
    @Override
    public void onSuccess(LocationSettingsResponse locationSettingsResponse) {
        // All location settings are satisfied. The client can initialize
        // location requests here.
        // ...
    }
});

task.addOnFailureListener(this, new OnFailureListener() {
    @Override
    public void onFailure(@NonNull Exception e) {
        if (e instanceof ResolvableApiException) {
            // Location settings are not satisfied, but this can be fixed
            // by showing the user a dialog.
            try {
                // Show the dialog by calling startResolutionForResult(),
                // and check the result in onActivityResult().
                ResolvableApiException resolvable = (ResolvableApiException) e;
                resolvable.startResolutionForResult(MainActivity.this,
                        REQUEST_CHECK_SETTINGS);
            } catch (IntentSender.SendIntentException sendEx) {
                // Ignore the error.
            }
        }
    }
});

打开应用程序设置并在用户启用/禁用某些功能后获得结果吗？

1 个答案: