Question

我收到此错误； “无法查询“ asd”：必须是“ OnlineGame”实例。”

（asd是gameslug）（OnlineGame是存储在线游戏名称（如大声笑）的类）

models.py

class Game(models.Model):
      match=models.ManyToManyField(Match,related_name="gamematch")

class Match(models.Model):
      teams = models.ManyToManyField(Team, through='MatchTeam')

class MatchTeam(models.Model):
    match = models.ForeignKey('Match', on_delete=models.CASCADE)
    team = models.ForeignKey(Team, on_delete=models.CASCADE)
    rank = models.IntegerField(default=20)
    point=models.IntegerField(default=0)

views.py

    game=get_object_or_404(Game
            ,tournament__slug=tournamentslug
            ,slug=slug,game__slug=gameslug)

    teams = MatchTeam.objects.filter(
    match__game=game
).annotate(
    points=F('rank')
).order_by(
    '-broyale_match', 'rank'
)

Answer 1

我将match__game替换为match__game__tournament__slug = tournamentslug，然后奏效了

Django ValueError“无法查询” asd“：必须是” OnlineGame“实例。

1 个答案: