Question

我有一个字典function twentynineteen_scripts() { wp_enqueue_style( 'twentynineteen-style', get_stylesheet_uri(), array(), wp_get_theme()->get( 'Version' ) ); wp_enqueue_script( 'twentynineteen-customControl', get_theme_file_uri( '/js/customize-controls.js' ), array('jquery'), '1.1', true ); wp_localize_script( 'customize-controls-script', 'php_obj', array( 'ajaxUrl' => admin_url( 'admin-ajax.php' ) ) ); } add_action( 'wp_enqueue_scripts', 'twentynineteen_scripts' ); add_action( 'wp_ajax_calendar_events', 'calendar_events_callback' ); add_action( 'wp_ajax_nopriv_calendar_events', 'calendar_events_callback' ); function calendar_events_callback() { exit(); }的列表，该字典具有相同的两个键，每个键在每个字典中具有不同的值。我希望它们以单一字典lst的形式出现其中两个键的所有值都列在列表中。请记住，键应从变量dict和dimLst中获取，否则它们是未知的。有什么想法吗？

metricLst

我希望输出像：

lst = [
    {'Location': 'ANNEX', 'ToTal_Dwell': 60.0},
    {'Location': 'CHENNAI', 'ToTal_Dwell': 86.0},
    {'Location': 'DADRI', 'ToTal_Dwell': 108.0},
    {'Location': 'JNPT', 'ToTal_Dwell': 39.0},
    {'Location': 'KOLKATA', 'ToTal_Dwell': 67.0},
    {'Location': 'MUNDRA', 'ToTal_Dwell': 82.0}
]

dimLst = ['Location']
metricsLst = ['ToTal_Dwell']

Answer 1

使用字典理解：

>>> {k: [d[k] for d in lst] for k in lst[0]}
{'Location': ['ANNEX', 'CHENNAI', 'DADRI', 'JNPT', 'KOLKATA', 'MUNDRA'], 'ToTal_Dwell': [60.0, 86.0, 108.0, 39.0, 67.0, 82.0]}

Answer 2

这是除字典理解之外的另一种解决方案

lst = [
    {'Location': 'ANNEX', 'ToTal_Dwell': 60.0},
    {'Location': 'CHENNAI', 'ToTal_Dwell': 86.0},
    {'Location': 'DADRI', 'ToTal_Dwell': 108.0},
    {'Location': 'JNPT', 'ToTal_Dwell': 39.0},
    {'Location': 'KOLKATA', 'ToTal_Dwell': 67.0},
    {'Location': 'MUNDRA', 'ToTal_Dwell': 82.0}
]

locationList = []
dwellList = []
locDict = {}

for i in lst:
    locationList.append(i['Location'])
    dwellList.append(i['ToTal_Dwell'])

locDict['Location'] = locationList
locDict['ToTal_Dwell'] = dwellList
print(locDict)

想要将字典列表转换为python中列表的列

2 个答案: