Question

我有一组类别标题。我想让函数从这些标题中返回ObjectId的数组。我该怎么办？

Category Model: {_id, title}


    const findCategoryIdsFromCategoryTitles = (titles) => {
        return Category.find({ title: { $in: titles } })._id
    }

    let titles = ["A1", "A2", "A3"]
    let categoryIds = findCategoryIdsFromCategoryTitles(titles)

Answer 1

您可以使用Mongoose .select（）方法选择特定字段。

const findCategoryIdsFromCategoryTitles = (titles) => {
    return Category.find({ title: { $in: titles } }).select('_id'); // Here you are selecting only _id field
}

Answer 2

第一个解决方案：select

const findCategoryIdsFromCategoryTitles = (titles) => {
    return Category.find({ title: { $in: titles } }).select({ "_id": 1}); // or select("_id")
}

let titles = ["A1", "A2", "A3"]
let categoryIds = findCategoryIdsFromCategoryTitles(titles)

使用aggregate

的第二个解决方案

const findCategoryIdsFromCategoryTitles = (titles) => {
    return Category.aggregate([{$match: {title: {$in: titles}}}, {$project: {_id: 1}}])
}

let titles = ["A1", "A2", "A3"]
let categoryIds = findCategoryIdsFromCategoryTitles(titles)

具有数组ID：

const findCategoryIdsFromCategoryTitles = async (titles) => {
    return await Category.find({ title: { $in: titles } }).select({ "_id": 1}); // or select("_id")
}
let categoryIds = await findCategoryIdsFromCategoryTitles(titles)
const result  = categoryIds.map(({_id})=>_id)

const result = [ { _id: '5d2e8ea173d1914ddee9443e' } , { _id: '5d2e8ea173d1914ddee94431' }].map(({_id})=>_id);

console.log(result);

Model.Find（）-如何返回ObjectId数组

2 个答案: