Question

所以我正在制作游戏并在进行Android手机测试时进行测试。当我统一单击鼠标按钮时，播放器将向左或向右移动，这正是我想要的。但这并不能很好地转化为我的Android手机。如果我快速快速地在屏幕上快速敲击两个拇指，则KINDA可以工作，这会使播放器快速左右摆动，但是如果我正常地在屏幕上多次敲击，播放器只会向一个方向移动。也许只是android，也许是我的代码，我不确定。谁能为我提供一些启发，或者可能告诉我如何解决？

我已经尝试了不同的鼠标输入代码，例如Input.GetButtonDown（“ Fire1”）和其他东西。但是，使它统一工作的原因是当我在每个函数的末尾添加return时。

using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.UI;
public class playerController : MonoBehaviour { 

private Rigidbody rb;
private Animator anim;
private bool left = false;
private bool right = false;
public static bool detect = false;
public float yspeed; //left or right from camera's vp
public float xSpeed = 55f; //down the road from camera's vp
[HideInInspector]
public bool crash = false;
public int slowSpeed;
private float respawnTimer = 3f;

void Start () {
    rb = GetComponent<Rigidbody> ();
    anim = GetComponent<Animator> ();
    rb.velocity = new Vector3 (xSpeed, rb.velocity.y, rb.velocity.z);
}


void Update () {    

    Movement ();
    Halt ();
}

public void Movement()
{
    if (crash) {
        left = false;
        right = false;
        scoreManager.scoreValue = 0;
    }
    detect = false;


    if (Input.GetMouseButtonDown (0) && !left){
        rb.velocity = new Vector3 (rb.velocity.x, yspeed, 0);
        left = true;
        right = false;
        return;

    }
    if (Input.GetMouseButtonDown (0) && !right){
        rb.velocity = new Vector3 (rb.velocity.x, -yspeed, 0);
        right = true;
        left = false;
        return;
    }
}

void OnTriggerEnter (Collider other)
{
    if (!crash && other.gameObject.tag == ("wall")) {
        crash = true;
        anim.SetTrigger ("crash");
    }

}
public void Halt()
{       
    if (crash && slowSpeed > 0) {
        rb.velocity = new Vector3 (--slowSpeed, 0, 0);
        Invoke ("Restart", respawnTimer);
    }
}

public void Restart ()
{

    Application.LoadLevel ("scene_01");
}
}

GetMouseButtonDown无法很好地翻译到android触摸屏

0 个答案: