Question

我正在尝试创建一个函数，它需要3个参数（List1，List2，“文件方向”）

该函数假定将两个列表按行串联在一起

List1 = [Paul, Jhon]

List2 = [Architect, Ingenieer]

直到列表为空。

Paul-建筑师

Jhon-工程师

我认为那里有问题

def appending(list1, list2, file):
    filetoopen = open(file, "a")
    for i in range(len(list1)):  # posible error acá, figure it out then
        filetoopen.write("\n" + list1[i] + " - " + list2[i] % (i+1))

    filetoopen.close()  # be sure you close the file before finish.


appending(names, work, "D:\papa.txt")

回溯（最近通话最近）：文件“ C：/Users/mauro/PycharmProjects/helloworld/writefiles.py”，第29行，在附加（名称，作品，“ D：\ papa.txt”）附加文件“ C：/Users/mauro/PycharmProjects/helloworld/writefiles.py”，第24行 filetoopen.write（“ \ n” + list1 [i] +“-” + list2 [i]％（i + 1）） TypeError：不是所有在格式化字符串期间转换的参数

Answer 1

尝试一下：

list1 = ["Paul", "Jhon"]

list2 = ["Architect", "Ingenieer"]

def appending(list1, list2, file):
    filetoopen = open(file, "w+")
    for i in range(len(list1)):  # posible error acá, figure it out then
        filetoopen.write("\n {0} - {1}".format(list1[i], list2[i], (i+1)))

    filetoopen.close()  # be sure you close the file before finish.

appending(list1, list2, "a.txt")

a.txt中的输出

 Paul - Architect
 Jhon - Ingenieer

Answer 2

出现此错误的原因仅仅是列表的成员不是字符串。一旦将它们用单引号或双引号引起来，就不会有错误。为了清楚起见，请看下面的代码-

def appending(list1, list2, file):
  filetoopen = open(file, 'a')
  for i in range(len(list1)):
    filetoopen.write(str(list1[i]) + " - " + str(list2[i]) + "\n")
  filetoopen.close()

List1 = ['Paul', 'Jhon']
List2 = ['Architect', 'Ingenieer']
filename = 'employee.txt'
appending(List1, List2, filename)

Answer 3

L1 = ['Paul', 'Jhon']
L2 = ['Architect', 'Ingenieer']
filename="pytest.txt"
def list_concat(L1,L2,filename):
    cL1=0
    if len(L1) == len(L2):
        with open(filename,'w') as writefile:
            while cL1 < len(L1):
                a = L1[cL1] + " " + L2[cL1] + '\n'
                writefile.write(a)
                cL1+=1
    else:
        pass
list_concat(L1,L2,filename)

Python函数写入文件

3 个答案: